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下面是一个Applet程序,其功能是有2个按钮,分别为First和Second,以及一个Label构件。要求单击First时则能在Label中显示出Command: First,而单击Second时则能显示出Command: Second,要求只能使用重载一次actionPerformed()方法。请改正程序中的错误(有下划线的语句),使程序能输出正确的结果。

注意:不改动程序的结构,不得增行或删行。

程序运行结果如下:

import java.awt.*;

import java.awt.event.*;

import java.applet.*;

/*

<applet code=ex3_3.class width=800 height=400>

</applet>

*/

public class ex3_3 extends Applet implements ActionListener

{

private String str="ok";

private Label 1;

private Button btn;

public void init( )

{

setLayout(null);

1=new Label(str);

1.reshape(10,10,150,30);

add(1);

btn=new Button("First");

btn.reshape(10,50,60,20);

1.addActionListener(this);

add(btn);

btn=new Button("Second");

btn.reshape(10,100,60,20);

btn.setActionCommand("First");

btn.addActionListener(this);

add(btn);

}

public void actionPerformed(ActionEvent ae)

{

str="Command:"+ae.getActionCommand( );

btn.setText(str);

}

}

ex3_3.html

<HTML>

<HEAD>

<TITLE>ex3_3</TITLE>

</HEAD>

<BODY>

<applet code="ex3_3.class"width=800 height=400>

</applet>

</BODY>

</HTML>


参考答案

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