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下面是某学生对一道习题的解答。    题目:质量为7.9 kg,边长为0.1m的正方体铁块放置在面积为0.5 平方米水平桌面上.它对水平桌面产生的压强是______________。       解:p=mg/S=(7.9 kgxlo N/kg)/0.5 ㎡-158 Pa    问题:    (1)简述该习题旨在帮助学生巩固的知识点及其要点。(4分)(2)指出学生解答中的错误,给出正确解法。(6分)    (3)针对作业的错误,设计一个教学片段或思路,帮助学生掌握正确分析和解决此类问题的方法。(10分)

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