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请编写冒泡排序算法,数据结构和函数原型定义如下: struct record { int key; int otheritem; }; typedef struct record RECORD; void bubblesort(RECORD R[],int n);
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int [] array = new int ;int temp = 0 ;for (int i = 0 ; i
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#define swap(a,b){a=a^b;b=a^b;a=a^b //交换a与b 的值int less(int x, int y){ return((xy)?1: 0);} void bubble Sort(int arr[ ], int n, int (*compare)(int, int)){ int i,j; int swapped= 1; for( i= 0; swapped; 1++) { swapped =0; for(j=0; j
【问题1】设有如下数组定义:int data1[ ]={4,2.6.3,1};int data2[ ]={4,2,6.3,1}int datas3[ ]={4,2,6.3,1}请分别给出下面的函数调用执行后,数组 data1、data2和 data3 各自的元素序列。(1)bubble Sort(data1, 5, less);(2)bubbleSort(data2, 5, larger)(3)bubbleSort(data3, 3, larger)
考题
多选题public class Transfers { public static void main(String[] args) throws Exception { Record r1 = new Record(); Record r2 = new Record(); doTransfer(r1, r2, 5); doTransfer(r2, r1, 2); doTransfer(r1, r2, 1); // print the result System.out.println(”rl = “ + r1.get() +“, r2=” + r2.get()); } private static void doTransfer( final Record a, final Record b, final int amount) { Thread t = new Thread() { public void run() { new Clerk().transfer(a, b, amount); } }; t.start(); } } class Clerk { public synchronized void transfer(Record a, Record b, int amount){ synchronized (a) { synchronized (b) { a.add(-amount); b.add(amount); } } } } class Record { int num=10; public int get() { return num; } public void add(int n) { num = num + n; } } If Transfers.main() is run, which three are true?()AThe output may be “r1 = 6, r2 = 14”.BThe output may be “r1 = 5, r2 = 15”.CThe output may be “r1 = 8, r2 = 12”.DThe code may run (and complete) with no output.EThe code may deadlock (without completing) with no output.FM IllegalStateException or InterruptedException may be thrown at runtime.
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