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有一电流表,其表头内阻R1为1Ω,量程I1为100mA,当并联R2=0.111Ω的分流电阻时,该表的量程I为多少安?若在此基础上把此表头改为I′=5A的量程,应并联多大分流电阻?
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更多 “有一电流表,其表头内阻R1为1Ω,量程I1为100mA,当并联R2=0.111Ω的分流电阻时,该表的量程I为多少安?若在此基础上把此表头改为I′=5A的量程,应并联多大分流电阻?” 相关考题
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以下能够正确计算n!的程序是( )。A.Private Sub Commandl_C1ick()B.hiVate Sub Commandl_C1ick() n=5:x=1 n=5:x=1:i=1 DO DO X=x*1 X=X*1 i=i+1 i=i+1 Loop while i<n Loop While<n Print x Ptinte x End Sub End SubC.Private Sub Commandl_Click ()D.Pdvate Sub Commandl C1ick() n=5:X=1:i=1 n=5=:x=1:i=1 DO DO X=X*1 X=X*1 i=i+1 i=i+1 Loop While i>n Print x Print x End Sub End Sub
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一表头Ig=1mA,Rg=1KΩ,此表作为直流电压表时,要求量程为100V,则应在表头()联接一个电阻,其阻值为()Ω;若改为量程为10mA的直流电流表,则在表头上()联接一个电阻,其阻值为()Ω。
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class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?() A、 0B、 1C、 2D、 Compilation fails.
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单选题class Super { public int i = 0; public Super(String text) { i = 1; } } public class Sub extends Super { public Sub(String text) { i = 2; } public static void main(String args[]) { Sub sub = new Sub(“Hello”); System.out.println(sub.i); } } What is the result?()A
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1C
2D
Compilation fails.
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问答题一个量程为1A的电流表,内阻r=0.5Ω,如果误将电流表接到电压U=220V的电源上,问通过电流表电流I有多大?将发生什么后果?
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