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（若oracle数据库不了解，可以用sql）
test1
ID Varchar2(6) 主键
NAME Varchar2(15)
Test2
Use_ID Varchar2(6) 主键关联TEST1的主键的ID
PASSword Varchar2(10)
参考答案
更多 “ （若oracle数据库不了解，可以用sql）test1ID Varchar2(6) 主键NAME Varchar2(15)Test2Use_ID Varchar2(6) 主键关联TEST1的主键的IDPASSword Varchar2(10) ” 相关考题
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The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER (4) NOT NULLCUSTOMER_NAME VARCHAR2 (100) NOT NULLSTREET_ADDRESS VARCHAR2 (150)CITY_ADDRESS VARHCAR2 (50)STATE_ADDRESS VARCHAR2 (50)PROVINCE_ADDRESS VARCHAR2 (50)COUNTRY_ADDRESS VARCHAR2 (50)POSTAL_CODE VARCHAR2 (12)CUSTOMER_PHONE VARCHAR2 (20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is.Which expression finds the number of different countries represented in the CUSTOMERS table?（）A. COUNT(UPPER(country_address))B. COUNT(DIFF(UPPER(country_address)))C. COUNT(UNIQUE(UPPER(country_address)))D. COUNT DISTINTC UPPER(country_address)E. COUNT(DISTINTC (UPPER(country_address)))
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The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER(4) NOT NULLCUSTOMER_NAME VARCHAR2(100) NOT NULLSTREET_ADDRESS VARCHAR2(150)CITY_ADDRESS VARCHAR2(50)STATE_ADDRESS VARCHAR2(50)PROVINCE_ADDRESS VARCHAR2(50)COUNTRY_ADDRESS VARCHAR2(50)POSTAL_CODE VARCHAR2(12)CUSTOMER_PHONE VARCHAR2(20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?（）A.COUNT(UPPER(country_address))B.COUNT(DIFF(UPPER(country_address)))C.COUNT(UNIQUE(UPPER(country_address)))D.COUNT DISTINCT UPPER(country_address)E.COUNT(DISTINCT (UPPER(country_address)))
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You executed the following code： SQL CREATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； In which tablespace will the mapping table be created？（）A、 SYSTEM tablespaceB、 SYSAUX tablespaceC、 Undo tablespaceD、 The tablespace of the Index Organized Table （IOT）
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考题
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The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which two statements find the number of customers? （） A、SELECT TOTAL(*) FROM customer;B、SELECT COUNT(*) FROM customer;C、SELECT TOTAL(customer_id) FROM customer;D、SELECT COUNT(customer_id) FROM customer;E、SELECT COUNT(customers) FROM customer;F、SELECT TOTAL(customer_name) FROM customer;
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You accepted the recommended SQL Profile by executing the following code： DECLARE sqlprofile_name varchar2（30）； BEGIN sqlprofile_name ：= DBMS_SQLTUNE.ACCEPT_SQL_PROFILE（ task_name = ’my_task’， profile_name = ’my_profile’）； END； Which advisor will analyze this profile？（） A、 SQL Access AdvisorB、 Undo AdvisorC、 Segment AdvisorD、 SQL Tuning Advisor
考题
You executed the following code： SQL CERATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； Which types of tables will be created automatically？（）A、 journal tableB、 clustered tableC、 mapping tableD、 partitioned table
考题
Examine the structure of the EMP_DEPT_VU view: Column Name Type Remarks EMPLOYEE_ID NUMBER From the EMPLOYEES table EMP_NAME VARCHAR2(30) From the EMPLOYEES table JOB_ID VARCHAR2(20) From the EMPLOYEES table SALARY NUMBER From the EMPLOYEES table DEPARTMENT_ID NUMBER From the DEPARTMENTS table DEPT_NAME VARCHAR2(30) From the DEPARTMENTS table Which SQL statement produces an error?（）A、SELECT*FROMemp_dept_vu；B、SELECTdepartment_id，SUM（salary）FROMemp_dept_vuGROUPBYdepartment_id；C、SELECTdepartment_id，job_id，AVG（salary）FROMemp_dept_vuGROUPBYdepartment_id，job_id；D、SELECTjob_id，SUM（salary）FROMemp_dept_vuWHEREdepartment_idIN（10，20）GROUPBYjob_idHAVINGSUM（salary）；20000；E、Noneofthestatementsproduceanerror；allarevalid
考题
The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) A promotional sale is being advertised to the customers in France. Which WHERE clause identifies customers that are located in France?（）A、WHERE lower(country_address) = "france"B、WHERE lower(country_address) = 'france'C、WHERE lower(country_address) IS 'france'D、WHERE lower(country_address) = '%france%'E、WHERE lower(country_address) LIKE %france%
考题
Evaluate the following code： SQLVARIABLE task_name VARCHAR2（255）； SQLVARIABLE sql_stmt VARCHAR2（4000）； SQLBEGIN ：sql_stmt ：= ’SELECT COUNT（*） FROM customers WHERE cust_state_province =’’CA’’’； ：task_name ：= ’MY_QUICKTUNE_TASK’； DBMS_ADVISOR.QUICK_TUNE（DBMS_ADVISOR.SQLACCESS_ADVISOR， ：task_name， ：sql_stmt）； END； What is the outcome of this block of code？（） A、 It creates a task and workload， and executes the task.B、 It creates a task and workload but does not execute the task.C、 It produces an error because a template has not been created.D、 It produces an error because the SQL Tuning Set has not been created.
考题
The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) Which statement finds the rows in the CUSTOMERS table that do not have a postal code? （）A、SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;B、SELECT customer_id, customer_name FROM customers WHER postal_code = ' ___________';C、SELECT customer_id, customer_name FROM customers WHERE postal _ code IS NULL;D、SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;E、SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;
考题
Examine the description of the CUSTOMERS table: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which statement returns the city address and the number of customers in the cities Los Angeles or San Francisco?（）A、SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco');B、SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address;C、SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address, customer_id;D、SELECT city_address, COUNT(customer_id) FROM customers GROUP BY city_address IN ('Los Angeles', 'San Francisco');
考题
The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER (4) NOT NULL CUSTOMER_NAME VARCHAR2 (100) NOT NULL STREET_ADDRESS VARCHAR2 (150) CITY_ADDRESS VARHCAR2 (50) STATE_ADDRESS VARCHAR2 (50) PROVINCE_ADDRESS VARCHAR2 (50) COUNTRY_ADDRESS VARCHAR2 (50) POSTAL_CODE VARCHAR2 (12) CUSTOMER_PHONE VARCHAR2 (20) The CUSTOMER_ID column is the primary key for the table. You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?（）A、COUNT(UPPER(country_address))B、COUNT(DIFF(UPPER(country_address)))C、COUNT(UNIQUE(UPPER(country_address)))D、COUNT DISTINTC UPPER(country_address)E、COUNT(DISTINTC (UPPER(country_address)))
考题
Scott issues the SQL statements: CREATE TABLE dept (deptno NUMBER(2), dname VARCHAR2(14), loc VARCHAR2(13)}; GRANT SELECT ON DEPT T0 SUE; If Sue needs to select from Scott's DEPT table, which command should she use?（）A、SELECT*FROMDEPT；B、SELECT*FROMSCOTT.DEPT；C、SELECT*FROMDBASCOTTDEPT；D、SELECT*FROMALL_USERSWHEREUSER_NAME='；SCOTT'；ANDTABLENAME='；DEPT'；；
考题
单选题FACULTY表包含以下各列： FACULTYID VARCHAR2(5) NOT NULL PRIMARY KEY FIRST_NAME VARCHAR2(20) LAST_NAME VARCHAR2(20) ADDRESS VARCHAR2(35) CITY VARCHAR2(15) STATE VARCHAR2(2) ZIP NUMBER(9) TELEPHONE NUMBER(10) STATUS VARCHAR2(2) NOT NULL COURSE 表包含以下各列： COURSEID VARCHAR2(5) NOT NULL PRIMARY KEY SUBJECT VARCHAR2(5) TERM VARCHAR2(6 FACULTYID VARCHAR2(5) NOT NULL FOREIGN KEY 您需要制定一个报表，用于确定在下学期任教的所有副教授。您要创建一个视图来简化报表的创建过程。以下哪条CREATE VIEW语句将完成此任务（）A
CREATE VIEW（SELECT first_name，last_name，status，courseid，subject，term FROM faculty，course WHERE facultyid=facultyid）B
CREATE VIEW pt_view ON（SELEC Tfirst_name，last_name，status，courseid，subject，term FROM faculty f and coursec WHERE f.facultyid=c.facultyid）C
CREATE VIEW pt_view IN（SELECT first_name，last_name，status，courseid，subject，term FROM faculty course）D
CREATE VIEW pt_view AS（SELECT first_name，last_name，status，courseid，subject，term FROM facultyf，coursec WHERE f.facultyid=c.facultyid）
考题
单选题You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: CUST_ID NUMBER(4) NOT NULL CUST_NAME VARCHAR2(100) NOT NULL CUST_ADDRESS VARCHAR2(150) CUST_PHONE VARCHAR2(20) Which SELECT statement accomplishes this task?（）A
SELECT* FROM customers;B
SELECT name, address FROM customers;C
SELECT id, name, address, phone FROM customers;D
SELECT cust_name, cust_address FROM customers;E
SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
考题
单选题The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?（）A
COUNT(UPPER(country_address))B
COUNT(DIFF(UPPER(country_address)))C
COUNT(UNIQUE(UPPER(country_address)))D
COUNT DISTINCT UPPER(country_address)E
COUNT(DISTINCT (UPPER(country_address)))
考题
单选题评估EMPLOYEE表的结构： EMPLOYEE_IDNUMBER（9） LAST_NAMEVARCHAR2（25） FIRST_NAMEVARCHAR2（25） DEPARTMENT_IDNUMBER（9） MANAGER_IDNUMBER（9） SALARYNUMBER（7，2） 您使用以下哪条语句可将LAST_NAME列（当前包含200条记录）的长度增加到35个字节（）A
ALTER employee TABLEAL TERCOLUMN（last_name VARCHAR2（35））B
ALTER TABLE employee RENAME last_name VARCHAR2（35）C
ALTER TABLE employee MODIFY（last_name VARCHAR2（35））D
不能增大LAST_NAME列的宽度
考题
单选题Evaluate the following code： SQLVARIABLE task_name VARCHAR2（255）； SQLVARIABLE sql_stmt VARCHAR2（4000）； SQLBEGIN ：sql_stmt ：= ’SELECT COUNT（*） FROM customers WHERE cust_state_province =’’CA’’’； ：task_name ：= ’MY_QUICKTUNE_TASK’； DBMS_ADVISOR.QUICK_TUNE（DBMS_ADVISOR.SQLACCESS_ADVISOR， ：task_name， ：sql_stmt）； END； What is the outcome of this block of code？（）A
It creates a task and workload， and executes the task.B
It creates a task and workload but does not execute the task.C
It produces an error because a template has not been created.D
It produces an error because the SQL Tuning Set has not been created.
考题
单选题You executed the following code： SQL CREATE TABLE COUNTRY （COUNTRY_ID CHAR（2） CONSTRAINT COUNTRY_ID_nn NOT NULL， COUNTRY_NAME VARCHAR2（20）， CURRENCY_NAME VARCHAR2（20）， CONSTRAINT COUNTRY_ID_PK PRIMARY KEY （COUNTRY_ID）） ORGANIZATION INDEX； In which tablespace will the mapping table be created？（）A
SYSTEM tablespaceB
SYSAUX tablespaceC
Undo tablespaceD
The tablespace of the Index Organized Table （IOT）
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