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苹果手机通讯录程序允许相同名字的联系人存在，编程将相同名字的联系人进行合并。输入为联系人的数量n（n＜ typedef struct friend char nameMAX_LEN long int phonenum int num FRIEND ds ld s ld n peter alice alice zhang peter alice zhang peter alice wang zhang peter alice wang zhang ＞
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更多 “苹果手机通讯录程序允许相同名字的联系人存在，编程将相同名字的联系人进行合并。输入为联系人的数量n（n＜ typedef struct friend char nameMAX_LEN long int phonenum int num FRIEND ds ld s ld n peter alice alice zhang peter alice zhang peter alice wang zhang peter alice wang zhang ＞” 相关考题
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若Alice要向Bob分发一个会话密钥，采用ElGamal公钥加密算法，那么Alice对该会话密钥进行加密应该选用的是（）。A.Alice的公钥B.Alice的私钥C.Bob的公钥D.Bob的私钥
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定义结构体数组：struct stu{int num;charname[20];}x[5]＝{1,"LI",2,"ZHAO",3,"WANG",4,"ZHANG",5,"LIU"};for(i＝1;i＜5;i++)printf("%d%C",x[i]．num,x[i]name[2]);以上程序段的输出结果为( )。A．2A3N4A5UB．112A3H41C．1A2N3A4UD．2H3A4H51
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定义结构体数组：struct stu{ int num;char name[20];}x[5]={1,"LI",2,"ZHAO",3,"WANG",4,"ZHANG",5,"LIU"};for(i=1;i＜5;i++)printf("%d%c",x[i].num,x[i].name[2];以上程序段的输出结果为( )。A．2A3N4A5UB．112A3H41C．1A2N3A4UD．2H3A4H51
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TALKING ABOUT BOXING DAYA. People will give money and other giftsB. Come on. Let s go.C. Boxing Day D. Well, I see.E. Yes, indeed so. _Zhang Hua and Peter are talking about Boxing Day after dinner._ …PETER：Do you know what do we call the day after Christmas DayZHANG HUA：(1)But I don t know much about it.PETER：Boxing Day is on December 26, the day after Christmas. People celebrate theholiday in many Commonwealth nations.ZHANG HUA：(2)What would you usually do on Boxing DayPETER：(3)to charitable institutions, needy individuals, and people in service jobs. And on that day, there are many discounts in the shopping centers and department stores.ZHANG HUA：I guess the shopping centers must be very crowded.PETER：(4)Do you want to go shoppingZHANG HUA：I won t miss this opportunity.PETER：I want to go too. (5)ZHANG HUA：All right.
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有以下程序：#includestruct stu { int num；char name[10]；int age；}void fun(struct stu*p){ printf(％s＼n，(*p).name)；}main{ struct stu students[3]={{9801，Zhang．20}， {9802，Wang，19}，{9803，Zhao，1 8}}fun(students+2)； }输出的结果是( )。A.ZhangB.ZhaoC.WangD.18
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The user Sue issues this SQL statement:GRANT SELECT ON sue. EMP TO alice WITH GRANT OPTION; The user Alice issues this SQL statement:GRANT SELECT ON sue. EMP TO reena WITH GRANT OPTION; The user Reena issues this SQL statement:GRANT SELECT ON sue. EMP TO timber;The user Sue issues this SQL statement:REVOKE select on sue. EMP FROM alice;For which users does the revoke command revoke SELECT privileges on the SUE.EMP table?（）A. Alice onlyB. Alice and ReenaC. Alice, Reena, and TimberD. Sue, Alice, Reena, and Timber
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有以下程序#include stdio.hstruct stu{ int num; char name [10]；int age；};Void fun(struct stu *p){ printf("%s＼n，p-name)；}main( ){ struct stu x[3]={ {01,”Zhang”,20}，{02, ” Wang”,19},{03, ”zhao”，18} }；fun(x+2);}程序运行后的输出结果是A)ZhangB)ZhaoC)WangD)19
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定义下列结构体(联合)数组： struct St { char name[15]； int age； }a[10]={"ZHAO",14,"WANG",15,"LIU",16,"ZHANG",17}； 执行语句printf("%d,%c",a[2].age,*(a[3].name+2))的输出结果为( )。A．15,AB．16,HC．16,AD．17,H
考题
有以下程序： #includestdio．h struct stu { int num；char name[l0]；int age；}； void fun(struct stu*p) { printf("%s\n"，p-name)；} main（ ） { struct stu x[3]={{01，"Zhang"，20)，{02，"Wang"，l9}，{03，"Zha0"，l8}}； fun(x+2)； } 程序运行后的输出结果是（ ）。A.ZhangB.ZhaoC.WangD.19
考题
有以下程序： #includestdio．h struct stu { int num； char name[10]： int age；} void fun(struct stu*p) {printf("％s＼n"，(*p)．name)；} the main { struct stu students[3]={{9801，"Zhang"．20}， {9802，"Wang"，19}，{9803，"Zhao"，1 8}} fun(students+2)； } 输出的结果是( )。A. ZhangB.ZhaoC.WangD.18
考题
以下程序的输出结果是______。includestruct stu{int num; char name[10]; int age;};v
以下程序的输出结果是______。#include＜stdio.h＞struct stu{ int num； char name[10]； int age；}；void fun(struct stu*p){ printf("%s\n"，(*p)．name)；}main(){ struct stu students[3]={ {9801，"Zhang"，20}， { 9802，"Wang"，19}， { 9803，"Zhao"，18} }； fun(students+2)；}A．ZhangB．ZhaoC．WangD．18
考题
●Alice发送带数字签名的消息共有以下4个步骤，步骤的正确顺序是(56) 。①Alice生成消息摘要 ②Alice生成消息③Alice发送消息 ④Alice利用私钥生成签名(56)A.①②③④B.①②④③C.②①④③D.②①③④
考题
Alice 发给 Bob 一个经 Alice 签名的文件，Bob 可以通过（16）验证该文件来源的合法性。A.Alice 的公钥
B.Alice 的私钥
C.Bob的公钥
D.Bob的私钥
考题
Alice发送带数字签名的消息共有以下4个步骤，步骤的正确顺序是（）。
①Alice生成消息摘要 ②Alice生成消息
③Alice发送消息 ④Alice利用私钥生成签名A.①②③④
B.①②④③
C.②①④③
D.②①③④
考题
以下哪种初始化数组的方式是错误的？（） A、 String[]names={"zhang"， "wang"， "li"）；B、 String names[] =new String [3]；names [0] ="zhang"； names [1] ="wang"； names [2] ="li"；C、 String[3] names={"zhang"， "wang"， "li"}；D、 以上皆正确
考题
The user Sue issues this SQL statement: GRANT SELECT ON sue. EMP TO alice WITH GRANT OPTION; The user Alice issues this SQL statement: GRANT SELECT ON sue. EMP TO reena WITH GRANT OPTION; The user Reena issues this SQL statement: GRANT SELECT ON sue. EMP TO timber; The user Sue issues this SQL statement: REVOKE select on sue. EMP FROM alice; For which users does the revoke command revoke SELECT privileges on the SUE.EMP table?（）A、Alice onlyB、Alice and ReenaC、Alice, Reena, and TimberD、Sue, Alice, Reena, and Timber
考题
单选题以下哪种初始化数组的方式是错误的？（）A
String[] name =，“zhang”，”wang”，”li”-B
String*3+ names=，“zhang”，”wang”，”li”-C
String names[] =new String[3] names*0+=”wang”D
names*1+=”wang”E
names*2+=”li”F
以上皆正确
考题
单选题有以下函数：#include struct stu{ int num; char name[10]; int age;};void fun(struct stu *p){ printf(%s, p-name);}main(){ struct stu x[3] = {{01,Zhang,20}, {02,Wang,19}, {03,Zhao,18}}; fun(x+2);}程序运行后的输出结果是（ ）。A
ZhangB
ZhaoC
WangD
19
考题
单选题以下哪种初始化数组的方式是错误的？（）A
String[]names={zhang， wang， li）；B
String names[] =new String [3]；names [0] =zhang； names [1] =wang； names [2] =li；C
String[3] names={zhang， wang， li}；D
以上皆正确
考题
单选题有如下程序：#include struct person{ char name[10]; int age;};main(){ struct person room[4] = {{Zhang,19}, {Li,20}, {Wang,17}, {Zhao,18}}; printf(%s:%d,(room+2)-name, room-age);}程序运行后的输出结果是（ ）。A
Wang:19B
Wang:17C
Li:20D
Li:19
考题
单选题— Please tell me ______ the scarf?— She bought it online, I guess.A
if Alice likedB
when Alice boughtC
where Alice boughtD
how much did Alice pay for
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