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题目内容 (请给出正确答案)
There is no ________, so we will begin with the next project.

A.objecting

B.objection

C.objected

D.object


参考答案

更多 “ There is no ________, so we will begin with the next project. A.objectingB.objectionC.objectedD.object ” 相关考题
考题 Stone is all around us. Stone is usually very hard, 46 it can also be soft. Stones have many uses.In some 47 , artists carve (雕刻) beautiful things out of soft stones, because they can be shaped easily. In ancient times, people carved 48 persons or animals out of soft stones, which could be carried along with. While in some European countries, statues (雕塑) are carved g49 hard stones and they do not change easily. In summer, the hot sun 50 on these statues and in winter the snow falls on them, but they 51 remain beautiful.Stone is strong and long-lasting. So, it is 52 enough for buildings. A house built of stone does not catch fire as easily as 53 made of wood. Some stones are coloured, so they make the 54 look wonderful. People can also get a fire with stones. Besides, some kinds of stones can be used to 55 jewellery (珠宝). We’ve found stones are really amazing.46.__________A. and B. but C. or D. so

考题 在循环双链表的p结点之后插入s结点的操作是______。A.p→next=s;p→next→prior=s;s→prior=p;s→next=p→next;B.s→!next=p;s→next=p→next;p→next=s;p→next→prior=s;C.p→next=s;s→prior=p;p→next→prior=s;s→next=p→next;D.s→prior=p;s→next=p→next;p→next→prior=s;p→next=s;

考题 You are using CTIDS in replication. You need to skip a transaction with the CTID of aaa-bbb-cccddd-eee : 3 on a slave. Which command would you execute from a Mysql prompt?() A.STOP SLAVE; SET GLOBAL SQL_SLAVE_SKIP_COUNTER=1; START SLAVEB.STOP SLAVE; BEGIN; SET GTID_IGNORE=aaa-bbb-ccc-ddd-eee: 3; COMMIT; START SLAVEC.STOP SLAVE; SETGTID_NEXT=aaa-bbb-ccc-ddd-eee: 3; BEGIN; COMMIT; SET GTID_NEXT=AUTOMATIC; START SLAVED.STOP SLAVE; RESET SLAVE; BEGIN; SKIP NEXT GTID; COMMIT; START SLAVE

考题 A simple master-to-slave replication is currently being used. The following information is extracted from the SHOW SLAVE STATUS output:Last_SQL_Error: Error 'Duplicate entry '8' for key 'PRIMARY A.SET GTID_NEXT=CONSISTENCY; BEGIN; COMMIT; SET GTID_NEXT=AUTOMATICB.SET GLOBAL enforce_gtid_consistency=ONC.SET GTID_EXECUTED=38f32e23480a7-32a1-c323f78067fd37821 : 9D.SET GTID_NEXT=38f32e23480a7-32a1-c323f78067fd37821 : 9; BEGIN; COMMIT; SET GTID_NEXT=AUTOMATICE.SET GLOBAL SQL_SKIP_SLAVE_COUNTER=1

考题 ____ were all very tired, but none of ____ would stop to take a rest. A、We ; usB、Us ; weC、We ; ourD、We ; we

考题 在循环双链表的p节点之后插As节点的操作是______。A.p→next=s; p→next→prior=s; s→prior=p; s→next=p→next;B.s→next=p; s→next=p→next; p→next=s; p→next→prior=s;C.p→next=s; s→prior=p; p→next→prior=s; s→next=p→next;D.s→prior=p; s→next=p→next; p→next→prior=s; p→next=s;

考题 在循环双链表的p结点之后插入s结点的操作是______。A.p→next=s; p→next→prior=s; S→prior=p; S→next=p→next;B.s→next=p; s→next=p→next; p→next=s; p→next→prior=s;C.p→next=s; s→prior=p; p→next→prior=s; s→next=p→next;D.s→prior=p; s→next=p→next; p→next→prior=s; p→next=S;

考题 在单链表中,删除p所指结点的直接后继的操作是 ( )A.p—>next=p—>next—>next;B.p=p—>next;p—>next=p—>next—>next;C.p—>next=p—>next;D.p=p—>next—>next;

考题 在循环双链表的p节点之后插入s节点的操作是______。A.p→next=s; p→next→prior=s; s→prior=p; S→next=p→next;B.s→next=p; s→next=p→next; p→next=S; p→next→prior=s;C.p→next=s; s→prior=p; p→next→prior=s; s→next=p→next;D.s→prior=p; s→next=p→next; p→next→prior=s; p→next=s;

考题 在一个双向链表中,若删除p所指结点的后继结点,应执行:A.p->next=p->next->next; p->next->next->prior=p;B.p=p->next; p->next=p->next->next;C.p->next=p->next;p->prior=p->next->prior;D.p->next->next->prior=p; p->next=p->next->next;