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classSuperFoo{2.SuperFoodoStuff(intx){3.returnnewSuperFoo();4.}5.}6.7.classFooextendsSuperFoo{8.//insertcodehere9.}下面哪三项分别插入到第8行,可以编译?()
A.intdoStuff(){return42;}
B.intdoStuff(intx){return42;}
C.FoodoStuff(intx){returnnewFoo();}
D.SuperFoodoStuff(intx){returnnewFoo();}
参考答案
更多 “ classSuperFoo{2.SuperFoodoStuff(intx){3.returnnewSuperFoo();4.}5.}6.7.classFooextendsSuperFoo{8.//insertcodehere9.}下面哪三项分别插入到第8行,可以编译?() A.intdoStuff(){return42;}B.intdoStuff(intx){return42;}C.FoodoStuff(intx){returnnewFoo();}D.SuperFoodoStuff(intx){returnnewFoo();} ” 相关考题
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现有:1.classHorseRadish{2.//insertcodehere3.protectedHorseRadish(intx){4.System.out.println(bokchoy);5.}6.}7.classWasabiextendsHorseRadish{8.publicstaticvoidmain(String[]args){9.Wasabiw=newWasabi();10.}11.}分别插入到第2行,哪两项允许代码编译并产生bokchoy输出结果?()A.//justacommentB.protectedHorseRadish(){}C.protectedHorseRadish(){this(42);}D.protectedHorseRadish(){newHorseRadish(42);}
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现有1.classCalc{2.publicstaticvoidmain(String[]args){3.try{4.intx=Integer.parselnt(42a);5.//insertcodehere6.System.out.print(oops);7.}8.}9.}下面哪两行分别插入到第五行,会导致输oops?()
A.}catch(IllegalArgumentExceptione){B.}catch(IllegalStateExceptionc){C.}catch(NumbelFormatExceptionn){D.}catch(ClassCastExceptionc){
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现有:1.classSuperFoo{2.SuperFoodoStuff(intx){3.returnnewSuperFoo();4.}5.}6.7.classFooextendsSuperFoo{8.//insertcodehere9.}和四个声明:FoodoStuff(intx){returnnewFoo();}FoodoStuff(intx){returnnewSuperFoo();}SuperFoodoStuff(intx){returnnewFoo();}SuperFoodoStuff(inty){returnnewSuperFoo();}分别插入到第8行,有几个可以通过编泽?()
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