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表达式[index for index，value in enumerate（[3，5，7，3，7]）ifvalue==max（[3，5，7，3，7]）]的值为（）。
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更多 “表达式[index for index，value in enumerate（[3，5，7，3，7]）ifvalue==max（[3，5，7，3，7]）]的值为（）。” 相关考题
考题
试题二（共15分）阅读下列说明，回答问题1至问题3，将解答填入答题纸的对应栏内。【说明】逻辑覆盖法是设计白盒测试用例的主要方法之一，它是通过对程序逻辑结构的遍历实现程序的覆盖。针对以下由C语言编写的程序，按要求回答问题。struct _ProtobufCIntRange{int start_value;unsigned orig_index;}；typedef struct _ProtobufCIntRange ProtobufCIntRange;int int_range_lookup (unsigned n_ranges, const ProtobufCIntRange *ranges, int value){unsigned start,n； ∥1start=0；n=n_ranges;while(n1){ //2unsigned mid= start+ n/2;if(value ranges[mid].start_value){ //3n=mid-start; //4}else if(value=ranges[mid].start value+(int)(ranges[mid+1].orig_index-ranges[mid].orig_index){ //5unsigned new_start= mid+1; //6n=start+n-new_start,start = new_start;}else //7return (value - ranges[mid].start_value)+ ranges[mid],orig_index;}if(n0){ //8unsigned start_orig_index= ranges[start].orig_index;unsigned range_size=ranges[start+1].orig_index - start_orig_index;if (ranges[start].start_value=value value (int)(ranges[start].start_value+ range_size》 //9, 10return (value - ranges[start].start_value)+start_orig_index; //11}retum -1, //12} //13【问题1】（5分）请给出满足100%DC（判定覆盖）所需的逻辑条件。【问题2】 (7分)请画出上述程序的控制流图，并计算其控制流图的环路复杂度V(G)。【问题3】（3分）请给出【问题2】中控制流图的线性无关路径。
考题
Consider the following:Which statement best describes the meaning of the value for the key_len column?()
A.It shows the total size of the index rowB.It shows how many columns in the index are examinedC.It shows the number of characters indexed in the keyD.It shows how many bytes will be used from each index row
考题
要求为当前表建立一个候选索引，索引表达式为“职工号”，索引名zgh，则下列各语句中，正确的是( )。A．INDEX ON职工号TAG zgh UNIQUEB．INDEX TO职工号TAG zgh UNIQUEC．INDEX ON职工号TAG zgh CANDIDATED．INDEX TO职工号TAG zgh CANDIDATE
考题
[说明] 逻辑覆盖法是设计白盒测试用例的主要方法之一，它是通过对程序逻辑结构的遍历实现程序的覆盖。针对以下由C语言编写的程序，按要求回答问题。
Struct_ProtobufCIntRange{
Int start_value;
Unsigned orig_index;
};
typedef struct_ProtobufCIntRange ProtobufCIntRange;
in tint_range_lookup(unsigned n_ranges,const ProtobufCIntRange*ranges,int value) {
unsigned start,n; //1
start=0;
n=n_ranges;
while (n>1) { //2
unsigned mid=start+n/2;
if（value n=mid-start; //4
}
else if (value>=ranges[mid].start_value+ (int)(ranges[mid+1].orig_index-ranges[mid].orig_index)) { //5
unsigned new_start=mid+1; //6
n=start+n-new_start;
start=new_start;
}
else //7
return(value-ranges[mid].start_value)+ranges[mid].orig_index;
}
if(n>0){ //8
unsigned start_orig_index=ranges[start].orig_index;
unsigned range_size=ranges[start+1].orig_index-start_orig_index;
if (ranges[start].start_valuereturn(value-ranges[start].start_value)+start_orig_index; //11
}
return -1; //12
} //13
5、[问题1] 请给出满足100%DC(判定覆盖)所需的逻辑条件。（6分）6、[问题2] 请画出上述程序的控制流图，并计算其控制流图的环路复杂度VG.。（6分）
7、[问题3] 请给出[问题2]中控制流图的线性无关路径。（4分）
考题
int index = 1； String test = new String； String foo = test[index]； What is the result？（）A、 Foo has the value “”B、 Foo has the value nullC、 An exception is thrownD、 The code will not compile
考题
int index = 1； boolean test = new Boolean； boolean foo= test [index]； What is the result？（）A、 Foo has the value of 0.B、 Foo has the value of null.C、 Foo has the value of true.D、 Foo has the value of false.E、 An exception is thrown.F、 The code will not compile.
考题
Given： 8.int index = 1： 9.Boolean [] test = new boolcan [3]； 10.boolcan foo = test [index]； What is the result（）？ A、 foo has the value of 0.B、 foo has the value of null.C、 foo has the value of true.D、 foo has the value of false.E、 An-exception is thrown.F、 The code will not compile.
考题
int index = 1； int foo = new int ； int bar = foo [index]； int baz = bar + index； What is the result？（）A、 Baz has the value of 0B、 Baz has the value of 1C、 Baz has the value of 2D、 An exception is thrown.E、 The code will not compile.
考题
int index = 1； String [] test = new String[3]； String foo = test[index]； What is the result？（） A、 Foo has the value “”B、 Foo has the value nullC、 An exception is thrownD、 The code will not compile
考题
Which two statements are true regarding B-tree indexs（）A、The leaf blocks in the index are doubly linked.B、The leaf node stores a bitmap for each key value.C、The rows with NULL value in key columns also have entries in the index.D、The deletion of a row from the table causes a logical deletion in index leaf block and the space becomesavailable for the new leaf entry
考题
Which two statements are true about a bitmap index？ （）A、It is recommended for the columns that have unique values.B、It can be converted to a B-tree index by using the ALTER INDEX command.C、It has a bitmap segment for each distinct value in the key column， containing a string of bits in which each bit represents the presence or absence of a key column value.D、Updating the key column locks the whole bitmap segment that contains the bit for the key value to be updated.
考题
Which statement describes the effect on an index， when the indexed column for the rows is updatedin the base table（）A、An update in a leaf row takes place.B、The index becomes invalid after the update.C、The leaf block containing the row to be updated is marked as invalid.D、A row in the leaf block of the index for the key value is logically deleted and a new leaf row is inserted
考题
Which two statements are true regarding B-tree index（）A、The leaf blocks in the index are doubly linked.B、The leaf node stores a bitmap for each key value.C、The rows with NULL value in key columns also have entries in the index.D、The deletion of a row from the table causes a logical deletion in index leaf block and the space becomes available for the new leaf entry.
考题
单选题int index = 1； boolean[] test = new Boolean[3]； boolean foo= test [index]； What is the result？（）A
Foo has the value of 0.B
Foo has the value of null.C
Foo has the value of true.D
Foo has the value of false.E
An exception is thrown.F
The code will not compile.
考题
单选题int index = 1； int foo = new int ； int bar = foo [index]； int baz = bar + index； What is the result？（）A
Baz has the value of 0B
Baz has the value of 1C
Baz has the value of 2D
An exception is thrown.E
The code will not compile.
考题
单选题int index = 1； int [] foo = new int [3]； int bar = foo [index]； int baz = bar + index； What is the result？（）A
Baz has the value of 0B
Baz has the value of 1C
Baz has the value of 2D
An exception is thrown.E
The code will not compile.
考题
单选题int index = 1； boolean test = new Boolean； boolean foo= test [index]； What is the result？（）A
Foo has the value of 0.B
Foo has the value of null.C
Foo has the value of true.D
Foo has the value of false.E
An exception is thrown.F
The code will not compile.
考题
多选题Which two statements are true about a bitmap index？ （）AIt is recommended for the columns that have unique values.BIt can be converted to a B-tree index by using the ALTER INDEX command.CIt has a bitmap segment for each distinct value in the key column， containing a string of bits in which each bit represents the presence or absence of a key column value.DUpdating the key column locks the whole bitmap segment that contains the bit for the key value to be updated.
考题
多选题Which two statements are true regarding B-tree index（）AThe leaf blocks in the index are doubly linked.BThe leaf node stores a bitmap for each key value.CThe rows with NULL value in key columns also have entries in the index.DThe deletion of a row from the table causes a logical deletion in index leaf block and the space becomes available for the new leaf entry.
考题
单选题Given： 8.int index = 1： 9.Boolean [] test = new boolcan [3]； 10.boolcan foo = test [index]； What is the result（）？A
foo has the value of 0.B
foo has the value of null.C
foo has the value of true.D
foo has the value of false.E
An-exception is thrown.F
The code will not compile.
考题
多选题Which two statements are true regarding B-tree indexs（）AThe leaf blocks in the index are doubly linked.BThe leaf node stores a bitmap for each key value.CThe rows with NULL value in key columns also have entries in the index.DThe deletion of a row from the table causes a logical deletion in index leaf block and the space becomesavailable for the new leaf entry
考题
单选题int index = 1； String test = new String； String foo = test[index]； What is the result？（）A
Foo has the value “”B
Foo has the value nullC
An exception is thrownD
The code will not compile
考题
单选题int index = 1； String [] test = new String[3]； String foo = test[index]； What is the result？（）A
Foo has the value “”B
Foo has the value nullC
An exception is thrownD
The code will not compile
考题
填空题已知x=[3，2，3，3，4]，那么表达式[index for index，value in enumerate（x）if value==3]的值为（）。
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