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1标准大气压等于0.1013MPa、10mH2O柱、760mmHg。


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考题 1标准大气压等于()MPa,等于()Kg/cm2,()mmHg。

考题 下面运行程序后,单击命令按钮,输出的结果是______。Private Sub Commandl_clck()Dim a%(1 To 4),b%(3 To 6),i%,s1,s2Fori=1 To 4a(i)=iNextiFor i=3 To 6b(i)=iNextis1=YAS(a)S2=YAS(b)Printt"s1=";S1"S2=";s2End Sub

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考题 下列程序的执行结果为Private Sub Command1_Click()Dim s1 As String, s2 As Strings1= "abcd"Call Transfer(s1, s2)Print s2End SubPrivate Sub Transfer (ByVal xstr As String, ystr As String)Dim tempstr As Stringi=Len(xstr)Do While i =1tempstr=tempstr + Mid(xstr, i, 1)i=i - 1Loopystr=te mpstrEnd Sub( )。A.dcbaB.abdcC.abcdD.dabc

考题 单击窗体时,下列程序的执行结果是Private Sub Invert(ByVal xstr As String, ystr As String)Dim tempstr As StringDim I As IntegerI=Len(xstr)Do While I =1tempstr=tempstr + Mid(xstr, I, 1)I=I - 1Loopystr=tempstrEnd SubPrivate Sub Form_Click()Dim s1 As String, s2 As Strings1= "abcdef"Invert s1, s2Print s2End Sub( )。A.abcdefB.afbecdC.fedcbaD.defabc

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考题 在窗体中添加一个名称为Command1的命令按钮,然后编写如下程序: Public x As Integer Private Sub Command1_Click() x=10 Call s1 Call s2 MSgBox x End Sub Private Sub s1() x=x+20 End Sub Private Sub s2() Dim x As Integer x=X+20 End Sub 窗体打开运行后,单击命令按钮,则消息框的输出结果为______。A.10B.30C.40D.50

考题 设字符串s1='ABCDEFG',s2='PQRST',则运算s=CONCAT(SUB(s1,2,LEN(s2)),SUB(s1,LEN(s2,2))后的串值为(65)。A.'ABCDEFEF'B.'BCDEFG'C.'BCPQRST'D.'BCQR'

考题 有如下程序 Private Sub Command1_Chck( ) s=0 DO s=(s+1) *(s+2) N=N+1 Loop Until s>=10 Prim N;s End Sub 运行后的输出结果是A.0 1B.30 30C.4 30D.2 12

考题 假定一个工程由一个窗体文件Form1和两个标准模块文件Model1及Model2 组成。 Model1代码如下: Public X As Integer Public Y As Integer Sub S1( ) x=1 S2 End Sub Sub S2( ) y=10 Form1.Show End Sub Model2的代码如下: Sub Main( ) S1 End Sub 其中Sub Main被设置为启动过程。程序运行后,各模块的执行顺序是( )。A.Form1→Model1→Model2B.Model1→Model2→Form1C.Model2→Model1→Form1D.Model2→Form1→Model1

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考题 在窗体中添加一个名称为Commandl的命令按钮,然后编写如下程序: Public x As Integer Private Sub Commandl_click() x=10 Call s 1 Call s 2 MsgBOx x End Sub Pfivate Sub s1() x=x+20 End Sub Private SubA.10B.30C.40D.50

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考题 下列程序的执行结果为 Private Sub Command1_C1ick( ) Dim sl As String,s2 AS String s1="abcdef" Call lnvert(s1,s2) Print s2 End Sub Private Sub lnvert(ByVal xstr As String,ystr As String) Dim tempstr As Stdng i=Len(xstr) Do While i>=1 tempstr=tempstr+Mid(xstr,i,1) i=i-1 Loop ystr=tempstr End SubA.fedcbaB.abcdefC.afbecdD.defabc

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考题 运行下列程序:Private Sub Command1_Click( )Dim s1 As String * 1Dim s2 As Strings1 = aFor i = Asc(s1) To Asc(s1) + 4s2 = s2 Chr(i)Next iPrint s2End Sub单击Command1命令按钮后,则在窗体上显示的结果是( )。A.aB.abcdeC.aaaaD.s2

考题 下列程序的执行结果为 Private Sub Command1_Click() Dim s1 As String,s2 As String S1;="abcdef" Call Invert(s1,s2) Print s2 End Sub Private Sub Invert (ByVal xstr As String,ystr As String) Dim tempstr As String i=Len(xstr) Do While i=1 tempstr=tempstr+Mid(xstr,i,1) i=i-1 Loop ystr=tempstr End SubA.fedcbaB.abcdefC.afbecdD.defabc

考题 有如下程序: Private Sub Command1_Click( ) a$="A WORKER IS OVER THERE" x=Len(a $) For i=1 To x-1 b$=Mid $(a $,i,2) If b $="ER"Then s=s+1 Next i Pdnt s End Sub 程序运行后的输出结果是A.1B.2C.3D.4

考题 下列程序的执行结果为 Private Sub Commandl_Click() Dim s1 As String ,s2 As String s1= "abcd" Call Transfer(sl,s2) Print s2 End Sub Private Sub Transfer (ByVal xstr As String,ystr As String) Dim tempstr As String ystr=tempstr End SubA.dcbaB.abdcC.abcdD.dabc

考题 设字符串S1= “ABCDEF”,S2= “PQRS”,则运算S=CONCAT(SUB(S1,2,LEN(S2)),SUB(S1,LEN(S2),2))后的串值为()。

考题 对于标准大气压,以下说法正确的是:()A、1个标准大气压约等于101kPaB、1个标准大气压可用1bar来表示C、1个标准大气压约等于14.7psiD、本题其他答案都正确

考题 1标准大气压等于()kgf/cm2,()bar,()mmHg,()Pa。

考题 填空题设字符串S1= “ABCDEF”,S2= “PQRS”,则运算S=CONCAT(SUB(S1,2,LEN(S2)),SUB(S1,LEN(S2),2))后的串值为()。