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由以下语句创建的表有种子字段,请正确组合插入语句,可不分先后。CREATE TABLE Customer(id int IDENTITY PRIMARY KEY,Customer varchar(40))()
A.INSERT INTO Customer
B.SET IDENTITY_INSERT Customer ON
C.VALUES（3，’garden shovel’）
D.（id，Customer）
参考答案
更多 “ 由以下语句创建的表有种子字段,请正确组合插入语句,可不分先后。CREATE TABLE Customer(id int IDENTITY PRIMARY KEY,Customer varchar(40))() A.INSERT INTO CustomerB.SET IDENTITY_INSERT Customer ONC.VALUES（3，’garden shovel’）D.（id，Customer） ” 相关考题
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欲创建如下数据表。“图书”表结构：书号：普通编码定长字符类型，长度为20，主键。书名：普通编码可变长字符类型，长度为40，非空。出版年份：整型。印刷数量：整型。单价：整型请补充完整SQL语句：CREATE TABLE 图书(书号 char(20) ______________ key,书名 varchar(40) not ______________,出版年份 int,印刷数量 int,单价 ______________)
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用以下SQL语句创建了表名为学生的关系表。create table 学生(学号 char(9) primary key,身份证号 char(18),姓名 varchar(8),性别 char(2),所属学院 varchar(20),专业 varchar (20),届次 char(4),出生日期 date,宿舍 int,简历 image);请写出查询全体学生的姓名及其年龄的SQL语句。
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Which statement accomplish this? ()
A. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);B. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);C. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);D. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);E. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);F. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
考题
You need to create a table named ORDERS that contain four columns:1. an ORDER_ID column of number data type2. aCUSTOMER_ID column of number data type3. an ORDER_STATUS column that contains a character data type4. aDATE_ORDERED column to contain the date the order was placed.When a row is inserted into the table, if no value is provided when the order was placed, today‘s date should be used instead.Which statement accomplishes this? （）A. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);B. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);C. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);D. CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);E. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);F. CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);
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阅读以下说明，回答问题1至问题3，将答案写在对应栏内。【说明】关于一位花商有以下一些事实。(1)销售在不同地区生长的花，这些地区一年的量低温度在一定范围内变化。(2)想用编号来表示发货类型。(3)要出售某些类型的花。假定已经通过SQL语句建立了基本表：CREATE TABLE Zone(ID Char(2) PRIMARY KEY，LowerTemp Number (3)，UpperTemp Number (3))；CREATE TABLE Delivery(ID char(2)PRIMARY KEY，Category VarChar (5)，DelSize Number (5，3))：CREATE TABLE FlowerInfo(ID Char(3) CONSTRAINTFlowerinfo_ id _ pk PRIMARY KEY，ComName VarChar (25)，LatName VarChar (30)，Czone Number (3)，Hzone Number (3)，Delivered Number (3)，SunNeed Char (3)，PRIMARY KEY (ID))：地区(ID，最高温度，最低温度)发货(ID，发货类型，发货规格)花的信息(ID，普通名，拉丁名，花能够生长的最冷地区，花能够生长的最热地区，发货类型，日光需求)写出语句，将(ID=1，Category=pot，DelSize=1.5)的数据插入DELIVERY表中。
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设有职工表（职工号，姓名，地址1，地址2），其中，职工号为主码。现要求地址1和地址2组合起来不能有重复值。在SQL Server 2008环境中有下列创建该表的语句：1．CREATE TABLE职工表（职工号int PRIMARY KEY，姓名nchar（10），地址1 nvarchar（20），地址2 nvarchar（20），UNIQUE（地址1，地址2））Ⅱ：CREATE TABLE职工表（职工号int PRIMARY KEY，姓名nchar（10），地址1nvarchar（20）．地址2 nvarchar（20）UNIQUE（地址1，地址2））Ⅲ．CREATE TABLE职工表（职工号int PRIMARY KEY．姓名nchar（10），地址1 nvarchar（20）UNIQUE，地址2 nvarchar（20）UNIQUE）IV．CREATE TABLE职工表（1职工号int PRIMARY KEY。姓名nchar（10），地址1 nvarchar（20）UNIQUE（地址1，地址2），地址2 nvarchar（20））上述语句能正确实现此约束的是（ ）。A.仅Ⅰ和ⅢB.仅Ⅱ和ⅣC.仅Ⅰ、Ⅱ和ⅣD.都正确
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某企业的数据库系统中有如下所示的员工关系和仓库关系，每个仓库可有多名员工，但只有一名负责人。员工关系(employee)：仓库关系(warehouse)：则创建仓库表结构的SQL语句为(58)。A．CREATE TABLE (employee ID CHAR(2)NOTNULL UNIQUE， name CHAR(30)NOT NULL， address CHAR(40)， principal ID CHAR(3))；B．CREATE warehouse(warehouse ID CHAR(2)PRIMARY KEY， name CHAR(30)， address CHAR(40)， principal ID CHAR(3))；C．CREATE TABLE warehouse(warehouse ID CHAR(2)PRIMARY KEY， name CHAR(30)NOT NULL， address CHAR(40)， principal ID CHAR(3)， FOREIGN KEY(principal ID)REFERENCES employee(employee ID))；D．CREATE TABIE warehouse(warehouse ID CHAR(2)， name CHAR(30)NOT NULL， address CHAR(40)， principal ID CHAR(3)， PRIMARY REY(warehouse ID)， FOREIGN KEY(employee ID)REFERENCES employee(employee ID))；
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68 、公司网络采用单域结构进行管理，域中有一台数据库服务器，为存贮公司数据，建立了名为information的数据库。管理员用以下语句建立了一个新表。CREATE TABLE emp_info(emp_ID int PRIMARY KEY,emp_Name varchar(50) UNIQUE,emp_Address varchar(50) UNIQUE)系统在该表上自动创建()索引。A 复合B 惟一C 聚集D 非聚集
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You need to create a table named ORDERS that contains four columns: 1.an ORDER_ID column of number data type 2.a CUSTOMER_ID column of number data type 3.an ORDER_STATUS column that contains a character data type 4.a DATE_ORDERED column to contain the date the order was placed When a row is inserted into the table, if no value is provided for the status of the order, the value PENDING should be used instead. Which statement accomplishes this?（）A、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status NUMBER(10) DEFAULT 'PENDING', date_ordered DATE );B、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );C、CREATE OR REPLACE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );D、CREATE OR REPLACE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) = 'PENDING', date_ordered DATE );E、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered DATE );F、CREATE TABLE orders ( order_id NUMBER(10), customer_id NUMBER(8), order_status VARCHAR2(10) DEFAULT 'PENDING', date_ordered VARCHAR2 );
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为表TEST中ID列添加主键约束的语法是（）A、ALTER TABLE TEST CHANGE（ ID INT PRIMARY KEY）B、ALTER TABLE TEST ADD（ ID INT PRIMARY KEY）C、ALTER TABLE TEST MODIFY（ ID INT PRIMARY KEY）D、ALTER TABLE TEST ADD CONSTRAINT PK PRIMARY KEY （ID）
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评估此CREATE TABLE语句的执行结果： CREATE TABLE part( part_id NUMBER, part_name VARCHAR2(25), manufacturer_id NUMBER(9), retail_price NUMBER(7,2) NOT NULL, CONSTRAINT part_id_pk PRIMARY KEY(part_id), CONSTRAINT cost_nn NOT NULL(cost), CONSTRAINT FOREIGN KEY (manufacturer_id) REFERENCES manufacturer(id)); 哪一行会导致产生错误（）A、6B、7C、8D、9
考题
“雇员”表包含以下列： EMPLOYEE_ID NOT NULL, Primary Key SSNUM NOT NULL, Unique LAST_NAME VARCHAR2(25) FIRST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER 部门表中 DEPARTMENT_ID 列的外键 SALARY NUMBER(8,2) 如果执行以下语句： CREATE INDEX emp_name_idx ON employees(last_name, first_name); 以下哪个说法是的（）A、此语句会创建一个基于函数的索引B、因为语法错误，此语句将失败C、该语句将创建一个组合唯一索引D、该语句将创建一个组合非唯一索引
考题
评估以下CREATETABLE语句的执行结果： CREATET ABLE customers （customer_id NUMBER，customer_name VARCHAR2（25）， address VARCHAR 2（25）， city VARCHAR 2（25）， region VARCHAR 2（25）， postal_code VARCHAR 2（11）， CONSTRAINT customer_id_un UNIQUE（customer_id）， CONSTRAINTcustomer_name_nnNOTNULL（customer_name））； 为什么执行时此语句会失败（）A、NUMBER数据类型要求精度值B、UNIQUE约束条件必须在列级定义C、CREATETABLE语句不定义PRIMARYKEYD、不能在表级定义NOTNULL约束条件
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Given the following requirements: Create a table to contain employee data, with a unique numeric identifier automatically assigned when a row is added, has an EDLEVEL column that permits only the values 'C', 'H' and 'N', and permits inserts only when a corresponding value for the employee's department exists in the DEPARTMENT table. Which of the following CREATE statements will successfully create this table?（）A、CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED ALWAYS AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1), PRIMARY KEY emp_pk (empno), FOREIGN KEY emp_workdept_fk ON (workdept) REFERENCES department (deptno), CHECK edlevel_ck VALUES (edlevel IN ('C','H','N')), );B、CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK edlevel VALUES ('C','H','N') );C、CREATE TABLE emp ( empno SMALLINT NEXTVAL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3) NOT NULL, edlevel CHAR(1) CHECK IN ('C','H','N')), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY department (deptno) REFERENCES (workdept) );D、CREATE TABLE emp ( empno SMALLINT NOT NULL GENERATED BY DEFAULT AS IDENTITY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, workdept CHAR(3), edlevel CHAR(1), CONSTRAINT emp_pk PRIMARY KEY (empno), CONSTRAINT emp_workdept_fk FOREIGN KEY (workdept) REFERENCES department (deptno), CONSTRAINT edlevel_ck CHECK (edlevel IN ('C','H','N')) );
考题
单选题假设需要更改表名“CUSTOMER”为“CUSTOMER_CHANGE”，可以使用（）语句。A
ALTER TABLE CUSTOMER RENAME CUSTOMER_CHANGEB
ALTER TABLE CUSTOMER RENAME TO CUSTOMER_CHANGEC
RENAME TABLE CUSTOMER TO CUSTOMER_CHANGED
RENAME TABLE CUSTOMER CUSTOMER_CHANGE
考题
单选题评估以下CREATETABLE语句的执行结果： CREATET ABLE customers （customer_id NUMBER，customer_name VARCHAR2（25）， address VARCHAR 2（25）， city VARCHAR 2（25）， region VARCHAR 2（25）， postal_code VARCHAR 2（11）， CONSTRAINT customer_id_un UNIQUE（customer_id）， CONSTRAINTcustomer_name_nnNOTNULL（customer_name））； 为什么执行时此语句会失败（）A
NUMBER数据类型要求精度值B
UNIQUE约束条件必须在列级定义C
CREATETABLE语句不定义PRIMARYKEYD
不能在表级定义NOTNULL约束条件
考题
单选题现有表book，字段：id（int），title（varchar），price（float）；其中id字段设为标识，使用insert语句向book表中插入数据，以下语句错误的是（）。A
insert into book（id，title，price）values（1，’java’，100）B
insert into book（title，price）values（’java’，100）C
insert into book values（’java’，100）D
insert book values（’java’，100）
考题
单选题The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER (4) NOT NULL CUSTOMER_NAME VARCHAR2 (100) NOT NULL STREET_ADDRESS VARCHAR2 (150) CITY_ADDRESS VARHCAR2 (50) STATE_ADDRESS VARCHAR2 (50) PROVINCE_ADDRESS VARCHAR2 (50) COUNTRY_ADDRESS VARCHAR2 (50) POSTAL_CODE VARCHAR2 (12) CUSTOMER_PHONE VARCHAR2 (20) The CUSTOMER_ID column is the primary key for the table. You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?（）A
COUNT(UPPER(country_address))B
COUNT(DIFF(UPPER(country_address)))C
COUNT(UNIQUE(UPPER(country_address)))D
COUNT DISTINTC UPPER(country_address)E
COUNT(DISTINTC (UPPER(country_address)))
考题
多选题由以下语句创建的表有种子字段，请正确组合插入语句，可不分先后。CREATE TABLE Customer（id int IDENTITY PRIMARY KEY，Customer varchar（40））（）AINSERT INTO CustomerBSET IDENTITY_INSERT Customer ONCVALUES（3，’garden shovel’）D（id，Customer）
考题
单选题评估此CREATE TABLE语句的执行结果： CREATE TABLE part( part_id NUMBER, part_name VARCHAR2(25), manufacturer_id NUMBER(9), retail_price NUMBER(7,2) NOT NULL, CONSTRAINT part_id_pk PRIMARY KEY(part_id), CONSTRAINT cost_nn NOT NULL(cost), CONSTRAINT FOREIGN KEY (manufacturer_id) REFERENCES manufacturer(id)); 哪一行会导致产生错误（）A
6B
7C
8D
9
考题
单选题DEPARTMENT 表包含以下列： DEPT_ID NUMBER, Primary Key DEPT_ABBR VARCHAR2(4) DEPT_NAME VARCHAR2(30) MGR_ID NUMBER EMPLOYEE 表包含以下列： EMPLOYEE_ID NUMBER EMP_LNAME VARCHAR2(25) EMP_FNAME VARCHAR2(25) DEPT_ID NUMBER JOB_ID NUMBER MGR_ID NUMBER SALARY NUMBER(9,2) HIRE_DATE DATE 请评估以下语句： ALTER TABLE employee ADD CONSTRAINT REFERENTIAL (mgr_id) TO department(mgr_id); 是以下哪个说法（）A
ALTER TABLE语句创建从EMPLOYEE表到DEPARTMENT表的引用约束条件B
ALTER TABLE语句创建从DEPARTMENT表到EMPLOYEE表的引用约束条件C
ADD CONSTRAINT子句存在语法错误，因此ALTER TABLE语句将会失败D
ALTER TABLE语句执行成功，但不重新创建引用约束条件
考题
单选题现有表book，字段：id（int），title（varchar），price（float）；其中id字段设为自增长的标识，使用insert语句向book表中插入数据，以下语句错误的是（）。A
insertintobook（id，title，price）values（1，’java’，100）B
insertintobook（title，price）values（’java’，100）C
insertintobookvalues（’java’，100）D
insertbookvalues（’java’，100）
考题
多选题The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which two statements find the number of customers?（）ASELECT TOTAL(*) FROM customer;BSELECT COUNT(*) FROM customer;CSELECT TOTAL(customer_id) FROM customer;DSELECT COUNT(customer_id) FROM customer;ESELECT COUNT(customers) FROM customer;FSELECT TOTAL(customer_name) FROM customer;
考题
单选题Examine the description of the CUSTOMERS table: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which statement returns the city address and the number of customers in the cities Los Angeles or San Francisco?（）A
SELECT city_address, COUNT(*) FROM customers WHERE city _ address IN ('Los Angeles','San Fransisco');B
SELECT city_address, COUNT (*) FROM customers WHERE city address IN ( 'Los Angeles', 'San Fransisco') GROUP BY city_address;C
SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ( 'Los Angeles', 'San Fransisco') GROUP BY city_address, customer_ id;D
SELECT city_address, COUNT (customer_id) FROM customers GROUP BY city_ address IN ('Los Angeles','San Fransisco');
考题
单选题“雇员”表包含以下列： EMPLOYEE_ID NOT NULL, Primary Key SSNUM NOT NULL, Unique LAST_NAME VARCHAR2(25) FIRST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER 部门表中 DEPARTMENT_ID 列的外键 SALARY NUMBER(8,2) 如果执行以下语句： CREATE INDEX emp_name_idx ON employees(last_name, first_name); 以下哪个说法是的（）A
此语句会创建一个基于函数的索引B
因为语法错误，此语句将失败C
该语句将创建一个组合唯一索引D
该语句将创建一个组合非唯一索引
考题
单选题The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?（）A
COUNT(UPPER(country_address))B
COUNT(DIFF(UPPER(country_address)))C
COUNT(UNIQUE(UPPER(country_address)))D
COUNT DISTINCT UPPER(country_address)E
COUNT(DISTINCT (UPPER(country_address)))
考题
单选题使用下列SQL语句创建教师表：CREATE TABLE教师表（教师编号I PRIMARY KEY，姓名C（8）NOT NULL，职称C（10）DEFAULT’讲师’）如果要删除“职称”字段的DEFAULT约束，正确的SQL语句是（ ）。A
ALTER TABLE教师表ALTER职称DROP DEFAULTB
ALTER TABLE教师表ALTER职称DELETE DEFAULTC
ALTER TABLE教师表DROP职称DEFAULTD
ALTER TABLE教师表DROP职称
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