The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（） A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.

考题 The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide? （）A. All of the desired resultsB. Two of the desired resultsC. One of the desired resultsD. An error statement

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考题 The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results? （）A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

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考题 Examine the data in the EMPLOYEES table:Which three subqueries work? () A. SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

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考题 The EMP table contains these columns:You need to display the employees who have not been assigned to any department.You write the SELECT statement:What is true about this SQL statement?() A. The SQL statement displays the desired results.B. The column in the WHERE clause should be changed to display the desired results.C. The operator in the WHERE clause should be changed to display the desired results.D. The WHERE clause should be changed to use an outer join to display the desired results.

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考题 Examine the data in the EMPLOYEES table:LAST_NAME DEPARTMENT_ID SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000...Which three subqueries work? () A. SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B. SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C. SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D. SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E. SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F. SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

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考题 Click the Exhibit button and examine the data in the EMPLOYEES table.Which three subqueries work? () A.SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C.SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D.SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E.SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F.SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

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考题 The EMPLOYEE tables has these columns: LAST_NAME VARCHAR2(35) SALARY NUMBER(8,2) COMMISSION_PCT NUMBER(5,2) You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column. Which SQL statement displays the desired results?（）A、SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;B、SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;C、SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;D、SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

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考题 Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?（）A、SELECT last_name, 12*salary* commission_pct FROM emp;B、SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C、SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D、SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

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考题 The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A、All of the desired resultsB、Two of the desired resultsC、One of the desired resultsD、An error statement

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考题 Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view? （）A、SELECT a.last_name, a.salary, a.department_id, b.maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;B、SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))C、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);D、SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

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考题 Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);C、SELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);D、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);E、SELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

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考题 The EMP table contains these columns: LAST NAME VARCHAR2(25) SALARY NUMBER(6,2) DEPARTMENT_ID NUMBER(6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARMENT_ID = NULL; What is true about this SQL statement? （）A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.

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考题 The EMP table contains these columns: LAST NAME VARCHAR2(25) SALARY NUMBER(6,2) DEPARTMENT_ID NUMBER(6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARMENT_ID = NULL; What is true about this SQL statement?（）A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.

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考题 Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）A、SELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);B、SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);C、SELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);D、SELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);E、SELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);F、SELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

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考题 Examine the structure of the EMP_DEPT_VU view: Column Name Type Remarks EMPLOYEE_ID NUMBER From the EMPLOYEES table EMP_NAME VARCHAR2(30) From the EMPLOYEES table JOB_ID VARCHAR2(20) From the EMPLOYEES table SALARY NUMBER From the EMPLOYEES table DEPARTMENT_ID NUMBER From the DEPARTMENTS table DEPT_NAME VARCHAR2(30) From the DEPARTMENTS table Which SQL statement produces an error?（）A、SELECT * FROM emp_dept_vu;B、SELECT department_id, SUM(salary) FROM emp_dept_vu GROUP BY department _ id;C、SELECT department_id, job_id, AVG(salary) FROM emp_dept_vu GROUP BY department _ id, job_id;D、SELECT job_id, SUM(salary) FROM emp_dept_vu WHERE department_id IN (10,20) GROUP BY job_id HAVING SUM (salary) 20000E、None of the statements produce an error; all are valid.

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考题 The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（）A、The SQL statement displays the desired results.B、The column in the WHERE clause should be changed to display the desired results.C、The operator in the WHERE clause should be changed to display the desired results.D、The WHERE clause should be changed to use an outer join to display the desired results.

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考题单选题Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees?（）A SELECT last_name, 12*salary* commission_pct FROM emp;B SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

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考题单选题Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) DEPARTMENT_ID NUMBER SALARY NUMBER What is the correct syntax for an inline view?（）A SELECT a.last_name, a.salary, a.department_id,B maxsal FROM employees a, (SELECT department_id, max(salary)maxsal FROM employees GROUP BY department_id) b WHERE a.department_id = b.department_id AND a.salary b.maxsal;C SELECT a.last name, a.salary, a.department_id FROM employees a WHERE a.department_id IN (SELECT department_id FROM employees b GROUP BY department_id having salary = (SELECT max(salary) from employees))D SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE a.salary = (SELECT max(salary) FROM employees b WHERE a.department _ id = b.department _ id);E SELECT a.last_name, a.salary, a.department_id FROM employees a WHERE (a.department_id, a.salary) IN (SELECT department_id, a.salary) IN (SELECT department_id max(salary) FROM employees b GROUP BY department_id ORDER BY department _ id);

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考题多选题Examine the data in the EMPLOYEES table: Which three subqueries work? （）ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

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考题单选题The EMP table contains these columns: LAST NAME VARCHAR2(25) SALARY NUMBER(6,2) DEPARTMENT_ID NUMBER(6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARMENT_ID = NULL; What is true about this SQL statement? （）A The SQL statement displays the desired results.B The column in the WHERE clause should be changed to display the desired results.C The operator in the WHERE clause should be changed to display the desired results.D The WHERE clause should be changed to use an outer join to display the desired results.

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考题单选题The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（）A The SQL statement displays the desired results.B The column in the WHERE clause should be changed to display the desired results.C The operator in the WHERE clause should be changed to display the desired results.D The WHERE clause should be changed to use an outer join to display the desired results.

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考题单选题The EMP table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) DEPARTMENT_ID NUMBER (6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARTMENT_ID = NULL; What is true about this SQL statement ?（）A The SQL statement displays the desired results.B The column in the WHERE clause should be changed to display the desired results.C The operator in the WHERE clause should be changed to display the desired results.D The WHERE clause should be changed to use an outer join to display the desired results.

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考题多选题Click the Exhibit button and examine the data in the EMPLOYEES table. Which three subqueries work?（）ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department_id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);CSELECT distinct department_id FROM employees WHERE salary ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);DSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);ESELECT last_name FROM employees WHERE salary ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));

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考题单选题The EMP table contains these columns: LAST NAME VARCHAR2(25) SALARY NUMBER(6,2) DEPARTMENT_ID NUMBER(6) You need to display the employees who have not been assigned to any department. You write the SELECT statement: SELECT LAST_NAME, SALARY, DEPARTMENT_ID FROM EMP WHERE DEPARMENT_ID = NULL; What is true about this SQL statement? （）A The SQL statement displays the desired results.B The column in the WHERE clause should be changed to display the desired results.C The operator in the WHERE clause should be changed to display the desired results.D The WHERE clause should be changed to use an outer join to display the desired results.

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考题单选题The EMPLOYEES table contains these columns: LAST_NAME VARCHAR2 (25) SALARY NUMBER (6,2) COMMISSION_PCT NUMBER (6) You need to write a query that will produce these results: 1. Display the salary multiplied by the commission_pct. 2. Exclude employees with a zero commission_pct. 3. Display a zero for employees with a null commission value. Evaluate the SQL statement: SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEES WHERE COMMISSION_PCT IS NOT NULL; What does the statement provide? （）A All of the desired resultsB Two of the desired resultsC One of the desired resultsD An error statement

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考题单选题Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns: LAST NAME VARCNAR2(35) NOT NULL SALARY NUMBER(9,2) NOT NULL COMMISION_PCT NUMBER(4,2) Which statement ensures that a value is displayed in the calculated columns for all employees? （）A SELECT last_name, 12*salary* commission_pct FROM emp;B SELECT last_name, 12*salary* (commission_pct,0) FROM emp;C SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;D SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;

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考题单选题Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables. EMPLOYEES NOT NULL, Primary EMPLOYEE_ID NUMBER Key VARCHAR2 EMP_NAME (30) VARCHAR2 JOB_ID (20) SALARY NUMBER References MGR_ID NUMBER EMPLOYEE_ID column DEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table DEPARTMENTS NOT NULL, DEPARTMENT_ID NUMBER Primary Key VARCHAR2 DEPARTMENT_NAME |30| References MGR_ID column MGR_ID NUMBER of the EMPLOYEES table TAX MIN_SALARY NUMBER MAX_SALARY NUMBER TAX_PERCENT NUMBER For which situation would you use a nonequijoin query?（）A To find the tax percentage for each of the employees.B To list the name, job id, and manager name for all the employees.C To find the name, salary, and department name of employees who are not working with Smith.D To find the number of employees working for the Administrative department and earning less then 4000.E To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.

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考题多选题Examine the data in the EMPLOYEES table: LAST_NAME DEPARTMENT_ID SALARY Getz 10 3000 Davis 20 1500 Bill 20 2200 Davis 30 5000 ... Which three subqueries work? （）ASELECT * FROM employees where salary (SELECT MIN(salary) FROM employees GROUP BY department _ id);BSELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department _ id);CSELECT distinct department_id FROM employees Where salary ANY (SELECT AVG(salary) FROM employees GROUP BY department _ id);DSELECT department_id FROM employees WHERE SALARY ALL (SELECT AVG(salary) FROM employees GROUP BY department _ id);ESELECT last_name FROM employees Where salary ANY (SELECT MAX(salary) FROM employees GROUP BY department _ id);FSELECT department_id FROM employees WHERE salary ALL (SELECT AVG(salary) FROM employees GROUP BY ANG (SALARY));

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