网友您好, 请在下方输入框内输入要搜索的题目:

题目内容 (请给出正确答案)

有如下类定义: class Test { public: Test(){a=0;c=0;} //① int f(int a)const {this->a=a;} //② static int g(){return a;} //③ void h(int b){Test::b=b;}; //④ private: int a; static int b; const int c; }; int Test::b=0; 在标注号码的行中,能被正确编译的是

A.①

B.②

C.③

D.④


参考答案

更多 “ 有如下类定义: class Test { public: Test(){a=0;c=0;} //① int f(int a)const {this->a=a;} //② static int g(){return a;} //③ void h(int b){Test::b=b;}; //④ private: int a; static int b; const int c; }; int Test::b=0; 在标注号码的行中,能被正确编译的是A.①B.②C.③D.④ ” 相关考题
考题 有如下类定义:class Test{public:Test(){ a = 0; c = 0;} // ①int f(int a)const{this-a = a;} // ②static int g(){return a;} // ③void h(intB . {Test::b = b;}; // ④private:int a;static int b;const int c;};int Test::b = 0;在标注号码的行中,能被正确编译的是A . ①B . ②C . ③D . ④

考题 有如下程序:includeusing namespace std;Class Test{public:Test(){n+=2;}~Test(){n- 有如下程序: #include<iostream> using namespace std; Class Test { public: Test() {n+=2;} ~Test() {n-=3;} static int getNum() {return n;} private: static int n; }; int Test::n=1; int main() { Test*p=new Test;A.n=0B.n=1C.n=2D.n=3

考题 有如下程序:includeusing namespace std;class test{private: int a;public: test( 有如下程序:#include<iostream>using namespace std;class test{private: int a;public: test(){cout<<"constructor"<<endl;} test(int a){cout<<a<<endl;} test(const test_test) { a=_test.a; cout<<"copy constructor"<<en+dl; } ~test(){cout<<"destructor"<<endl;}};int main(){ test A(3); rerun 0;}运行时输出的结果是A.3B.constructor destructorC.copy constructor destructorD.3 destructor

考题 如下程序的输出结果是includeusing namespace std;class Test{public:Test( ){n+=2;} 如下程序的输出结果是 #include<iostream> using namespace std; class Test{ public: Test( ){n+=2;} ~Test( ){n-=3;} static int getNum( ){return n;} private: static int n; }; int Test::n=1; int main( ){ Test*P=new Test: delete P; cout<<"n="<<Test::getNum( )<<endl; return 0; }A.n=0B.n=1C.n=2D. n=3

考题 有如下程序:include usingnamespacestd:class Test{public: Test(){n+=2; ~Test(){n- 有如下程序:#include <iostream>using namespace std:class Test{public: Test() {n+=2; ~Test() {n-=3; ; static int getNum() {return n;}privaue: static int n:};int Test::n=1;int main(){ Test* p=new Test; delete p; cout<<"n="<<Test::getNum()<<end1; return 0;} 执行后的输出结果是A.n=0B.n=1C.n=2D.n=3

考题 有如下类定义: class Test { public: Test(){a=0;c=0} //① int f(int a)const{this->a=a;} //② static int g(){return a;} //③ void h(int b){Test::b;}; //④ private: int a; static int b; const int C; }; int Test::b=0; 在标注号码的行中,能被正确编译的是( )。A.①B.②C.③D.④

考题 有如下程序:include using namespace std;class Test{public:Test(){n+=2; }~Test(){ 有如下程序: #include <iostream> using namespace std; class Test { public: Test() {n+=2; } ~Test() {n-=3; } static int getNum() {return n; } private: static int n; }; int Test::n=1; int main() { Test* p=new Test; delete p; cout<<"n="<<Test::getNum()<<endl; return 0; } 执行该程序的输出结果是( )。A.n=0B.n=1C.n=2D.n=3

考题 有如下类定义: class Test { public: Test{a=0;c=0;}//① int f(im A.const{this-a=a;}//② static int g{return a;f//③ void h(int B.{Test:.b=b;};//④ private: int a; static int b; const int C; }; int Test::b=0: 在标注号码的行中,能被正确编译的是( )。A.①B.②C.③D.④

考题 有如下类定义: class Test { int x_,y_; public: Test ():a_(0) ,b_(0) {} Test(int a,int b=0) :a_(a),b_(b){} }; 若执行语句 Test x(2) ,y[3],*z[4]; 则Test类的构造函数被调用的次数是( )。A.2次B.3次C.4次D.5次