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The student _________ English in class.
A.speak
B.speaks
C.speaking
D.to speak
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更多 “ The student _________ English in class. A.speakB.speaksC.speakingD.to speak ” 相关考题
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c＋＋,运行下面代码出错
#include iostreamusing namespace std;struct student_info{ string name; int chinese; int math; int english;};student_info student[5];void inputinfo(){ int i = 0; char a[20]; for(i = 0;i 5;i++) { cout"enter the "i+1" student's information "endl; cout"enter the name"endl; cina; student[i].name = a; cout"enter chinese performance :"endl; cinstudent[i].chinese; cout"enter math performance :"endl; cinstudent[i].math; cout"enter english performance :"endl; cinstudent[i].english; }}void outputinfo(){ int i = 0; while(i 5) { couti+1" student's information"endl; coutstudent[i].name.c_str()endl; cout"chinese "endl; coutstudent[i].chineseendl; cout"math "endl; coutstudent[i].mathendl; cout"english "endl; coutstudent[i].englishendl; i++; }}int avgfunction(int arr[],int n){ int i = 0; int total = 0; for(i = 0;i n;i++) { total += arr[i]; } return total / n;}void computavg() //这里是否正确？{ int theavg = 0; theavg = avgfunction(student[i].chinese,5); }int main(){ inputinfo(); outputinfo(); computavg(); cin.get(); return 0;} 帮我找出错误 然后改过来 择优为满意答案 不分先后
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阅读下列程序说明和C++代码，将应填入(n)处的字句写在对应栏内。[说明]①定义私有数据成员code、english分别用于表示考生的编号、英语成绩，它们都是int型的数据。②完成成员函数void Student::inputinformation()的定义，该函数用于用户输入一个考生对象的信息，输入格式如下：输入编号：英语成绩：计算机成绩：③利用已实现的类Student的成员函数，完成函数void firstname(Student *A[]，int uum)的定义，该函数根据考生信息A[]，输出num个考生中总分最高者的编号及其相应的总分，在此不考虑总分相同的情况。源程序文件test1.cpp清单如下：include ＜ iostream. h ＞class Student(1)int computer;int total;publicvoid getinformation( );void computesum( );int getcode( );int gettotalscore( );~Student( );};void Student: :getinformation( ){(2)cout ＜＜"英语成绩:";cin＞ ＞english;cout ＜＜"计算机成绩:";cin ＞ ＞ computer;void Student:: computesum ( )total = english + computer;cout ＜＜"编号" ＜＜ code ＜＜"总分:" ＜＜total ＜＜ endl;int Student::getcode( )return code;}int Student:: gettotalscore ( ){return total;}void firstname(Student * A[] ,int num){(3)tempsum = ( * A[0] ). gettotalscore( );for( int i=1; i ＜num; i++){if ( ( ( * A[i] ). gettotalscore( ) ) ＞ tempsum){tempcode = ( * A[i] ). getcode( );tempsum = ( * A[i] ). gettotalscore( );}}cout ＜＜"总分最高者--" ＜＜ tempcode ＜＜":" ＜＜ tempsum ＜＜endl;}void main( ){Student * A[3];int i,n =3for(i=0;i＜n;i ++)A[i] = new Student;A[i] -＞ getinformation( )for(i=0;i＜n;i ++){A[i] -＞ computesum( )firstname ( A,3 );}
考题
将“模拟试卷六”文件夹下WANGWILM文件夹中的文件RAIN.SOP移动到“模拟试卷六”文件夹下STUDENT\ENGLISH文件夹中，并更名为BEAUTY.BAS。(2)在“模拟试卷六”文件夹下WORK文件夹中建立一个新文件夹PLAN。(3)将“模拟试卷六”文件夹下WANG文件夹中的文件夹GAME设置为只读和隐藏属性。(4)将“模拟试卷六”文件夹下WANG\MUSIC文件夹中的文件moon. stp删除。(5)将“模拟试卷六”文件夹下STUDENT文件夹中的文件夹ENGLISH复制到“模拟试卷六”文件夹下的WORK文件夹中。
考题
Which statement explicitly names a constraint? ()
A. ALTER TABLE student_grades ADD FOREIGN KEY (student_id) REFERENCES students (student_id);B. ALTER TABLE student_grades ADD CONSTRAINT NAME = student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id);C. ALTER TABLE student_grades ADD CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id);D. ALTER TABLE student grades ADD NAMED CONSTRAINT student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id);E. ALTER TABLE student grades ADD NAME student_id_fk FOREIGN KEY (student_id) REFERENCES students (student_id);
考题
为choose表添加外键约束，约束名为choose_student_fk，外键为student_no，连接到 student表的stuednt_no字段，以下命令正确的是______。A．alter table choose add constraint choose_student_fk FOREIGN KEY (student_no) ;B．alter table choose add constraint choose_student_fk FOREIGN KEY (student_no) REFERENCES student(stuednt_no);C．alter table choose add constraint choose_student_fk FOREIGN KEY (student_no) REFERENCES student;D．alter table choose add constraint choose_student_fk REFERENCES student(stuednt_no);
考题
1、Chinese: 一分耕耘，一分收获；English: No pains, no gains. What’s the translation skill used in this example of Chinese-to-English _______？A．Sentence divisionB．AffirmationC．TranspositionD．Negation
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