网友您好, 请在下方输入框内输入要搜索的题目:

题目内容 (请给出正确答案)
A frustrated and angry customer calls in with a system that does not work. Which of the following is the FIRST course of action for a technician to take?()

A. Transfer the customer to another technician, who can allocate more time to the issue.

B. Maintain a positive attitude and offer them the cheapest solution possible to satisfy them.

C. Listen to what the customer has to say and calmly recommend the best course of action.

D. Use technical language to demonstrate knowledge and expertise to the customer.


参考答案

更多 “ A frustrated and angry customer calls in with a system that does not work. Which of the following is the FIRST course of action for a technician to take?() A. Transfer the customer to another technician, who can allocate more time to the issue.B. Maintain a positive attitude and offer them the cheapest solution possible to satisfy them.C. Listen to what the customer has to say and calmly recommend the best course of action.D. Use technical language to demonstrate knowledge and expertise to the customer. ” 相关考题
考题 PublicclassHoltextendsThread{PrivateStringsThreadName;Publicstaticvoidmain(Stringargv[]){Holth=newHolt();h.go();Holt(){};Holt(Strings){sThreadName=s;PublicStringgetThreadName(){returnsThreadName;}}Publicvoidgo(){Hotfirst=newHot(first);first.start();Hotsecond=newHot(second);second.start();}Publicvoidstart(){For(inti=0;i2;i++){System.out.print(getThreadName()+i);Try{Thread.sleep(100);}catch(Exceptione){System.out.print(e.getMessage());}}}}当编译运行上面代码时,将会出现()A.编译时错误B.输出first0,second0,first0,second1C.输出first0,first1,second10,second1D.运行时错误

考题 Between labor and play______(stand)work.

考题 You’re going to have a quiz ( )by another two in the ( )month. A. followed,followedB. followed,followingC. following,followedD. following,following

考题 Giventhefollowingcode:if(x0){System.out.println(first);}elseif(x-3){System.out.println(second);}else{System.out.println(third);}Whichrangeofxvaluewouldprintthestringsecond?()A.x0B.x-3C.x=-3D.x=0x-3

考题 下列语句在控制台上的输出是().if(true)System.Console.WriteLine("First");System.Console.WriteLine("Second");A. FirstSecondB. FirstC. SecondD. 无输出

考题 阅读以下说明和 Java程序,填补代码中的空缺,将解答填入答题纸的对应栏内。 【说明】 以下Java代码实现一个简单客户关系管理系统(CRM)中通过工厂(CustomerFactory )对象来创建客户(Customer)对象的功能。客户分为创建成功的客户(RealCustomer)和空客户 (NullCustomer)。空客户对象是当不满足特定条件时创建或获取的对象。类间关系如图 5-1 所示。图5-1 类图【Java代码】 Abstract class Customer﹛ Protected String name; ( 1 )boolean isNil(); ( 2 )String getName(); ﹜ Class RealCustomer ( 3 )Customer{ Public RealCustomer(String name){ this.name=name; } Public String getName(){ return name ; } Public boolean is Nil() { return false; } ﹜ Class NullCustomer( 4 )Customer﹛ Public String getName()﹛ return Not Available in Customer Database; ﹜ Public boolean isNil() ﹛ return true; ﹜ ﹜ class Customerfactory { public String[] names = {Rob,Joe,Julie}; public Customer getCustomer(String name) { for (int i = 0; i names.length;i++) { if (names[i].( 5 ))﹛ return new RealCustomer(name); ﹜ ﹜ return ( 6 ); ﹜ ﹜ Public class CrM﹛ Public viod get Customer()﹛ Customerfactory( 7 ); Customer customer1-cf.getCustomer(Rob); Customer customer2=cf.getCustomer(Bob); Customer customer3= cf.getCustomer(Julie); Customer customer4= cf.getCustomer(Laura); System.out.println(customers) System.out.println(customer1.getName()); System.out.println(customer2getName()); System.out.println(customer3.getName()); System.out.println(customer4.getName()); ﹜ Public static viod main (String[]arge)﹛ CRM crm =new CRM(); Crm.getCustomer(); ﹜ ﹜ /*程序输出为: Customers rob Not Available in Customer Database Julie Not Available in Customer Database */

考题 4.—_________ Mike________ his homework in the evening?—No,he doesn't.A. Do;doesB. Does;doC. Do;doD. Does;does

考题 Which of the following may illustrate the difference between "competence" and__________ "performance"? A.What a person "knows" and what he/she "does". B.What a person "can do" and what he/she "does". C.What a person "does" and what he/she "knows". D.What a person "does" and what he/she "can do".

考题 Action API完成返回数据集中的元素个数的操作命令是()。A.first()B.reduce(func)C.count()D.take(n)

考题 Action API完成返回数据集中的前n个元素的操作命令是()。A.first()B.reduce(func)C.count()D.take(n)