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What are two rules for compacting IPv6 addresses？（）
- A、The maximum number of times a double colon can replace a 16-bit segment that consists of all zeroes is two
- B、The leading zeroes in any 16-bit segment do not have to be written.
- C、Every 16-bit segment that consists of all zeroes can be represented with a single colon
- D、The trailing zeroes in any 16-bit segment do not have to be written.
- E、Any single， continuous string of one or more 16-bit segments that consists of all zeroes can be represented with a double colon
- F、Two zeroes in the middle of any 16-bit segment do not have to be written
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更多 “What are two rules for compacting IPv6 addresses？（）A、The maximum number of times a double colon can replace a 16-bit segment that consists of all zeroes is twoB、The leading zeroes in any 16-bit segment do not have to be written.C、Every 16-bit segment that consists of all zeroes can be represented with a single colonD、The trailing zeroes in any 16-bit segment do not have to be written.E、Any single， continuous string of one or more 16-bit segments that consists of all zeroes can be represented with a double colonF、Two zeroes in the middle of any 16-bit segment do not have to be written” 相关考题
考题
when the system upon which a transport entity is running fails and subsequently reatarts，the（）information of all active connections is lost.the affected connections become half-open，as the side that did not fail does not yet realize the promble. The still active side of a half-open connections using a（）timer.this timer measures the time transport machine will continue to await an（）of a transmitted segment after the segment has been retransmitted the maximum number of times.when the timer（），the transport entity assumes that either the other transport entity or the intervening network has failed.as a result，the timer closes the connection，and signals an abnormal close to the TS user. In the event that a transport entity fails and quickly restart，half-open connections can be teminated more quickly by the use of the RST segment.the failed side returns an RST I to every segment I that it receives.when the RST I reaches the other side，it must be checked for validity dased on the （）number I，as the RST could be in response to an old segment .if the reset is valid，the transport entity performs an abnormal termination.A.data B.state C.signal D.control A.give-up B.abandon C.quit D.connection A.reset B.acknowledgment C.sequence D.synchroizer A.stops B.restarts C.expires D.abandons A.sequence B.acknowledgment C.connection D.message
考题
You are the administrator of your company's network. The network is configured as shown in the exhibit.You want to install Windows 2000 Professional on 10 non-PXE-compliant computers that are on the marketing segment of your network. You start one of the computers by using a RIS boot disk. However, you cannot connect to the RIS server.You verify that the existing client computers on the network can connect to network servers, including the RIS server. The network router does not support BOOTP, so existing client computers use manually configured TCP/IP addresses. You want to enable the computers to connect to the RIS server.What should you do?A．Add a computer running DHCP Relay Agent to the marketing segment.B．Add a computer running the network monitor driver to the marketing segment.C．Move the Windows 2000 Server computer running WINS to the marketing segment.D．Move the Windows 2000 Server computer running Active Directory to the marketing segment.
考题
Which statement is correct regarding IPv6 addresses?()
A. An IPv6 address consists of 128 bits separated into eight 16-bit hexadecimal sections.B. An IPv6 address consists of 64 bits separated into four 16-bit hexadecimal sections.C. An IPv6 address consists of 128 bits separated into sixteen 8-bit hexadecimal sections.D. An IPv6 address consists of 64 bits separated into eight 8-bit hexadecimal sections.
考题
Regarding PAR (Positive Acknowledgement and Re－transmission), which of the answer choices below are correct?()
A. The source device will only retransmit lost packets on the request of the destination device.B. The source device starts a timer when it sends a segment and retransmits if an acknowledgment is not received before the timer expires.C. The destination device acknowledges receipt of a segment by sending a packet with a new sequence number and the ACK bit sent.D. The destination device acknowledges receipt of a segment by sending a packet that indicates the next sequence number it expects.E. If the destination device does not receive a segment, all segments are retransmitted.F. The source device keeps a record of all segments sent and expects and acknowledgment of each.
考题
What are two rules for compacting IPv6 addresses?()
A. Every 16 - bit segment segment that consists of all zeroes can be represented with a single colon.B. The trailing zeroes in any 16 - bit segment do not have to be written.C. The leading zeroes in any 16 - bit segment do not have to be written.D. Any single, continuous string of one or more 16 - bit segments that consists of all zeroes can be represented with a double colon.E. The maximum number of times a double colon can replace a 16 - bit segment that consists of all zeroes is two.F. Two zeroes in the middle of any 16 -bit segment do not have to be written.
考题
The Testking corporate LAN consists of one large flat network. You decide to segment this LAN into two separate networks with a router. What will be the affect of this change?()
A. The number of broadcast domains will be decreased.B. It will make the broadcasting of traffic between domains more efficient between segments.C. It will increase the number of collisions.D. It will prevent segment 1‘s broadcasts from getting to segment 2.E. It will connect segment 1‘s broadcasts to segment 2.
考题
When the system upon which a transport entity is running fails and subsequently restarts, the(66)information of all active connections is lost. The affected connections become half-open, as the side that did not fail does not yet realize the problem.The still active side of a half-open connection can close the connection using a(67)timer. This timer measures the time the transport machine will continue to await an(68)of a transmitted segment after the segment has been retransmitted the maximum number of times. When the timer(69), the transport entity assumes that either the other transport entity or the intervening network has failed. As a result, the timer closes the connection, and signals an abnormal close to the TS user.In the event that a transport entity fails and quickly restarts, half-open connections can be terminated more quickly by the use of the RST segment. The failed side returns an RST i to every segment i that it receives. When the RST i reaches the other side, it must be checked for validity based on the(70)number i, as the RST could be in response to an old segment. If the reset is valid, the transport entity performs an abnormal termination.A．dataB．stateC．signalD．control
考题
What are two rules for compacting IPv6 addresses?（）A、Every 16 - bit segment segment that consists of all zeroes can be represented with a single colon.B、The trailing zeroes in any 16 - bit segment do not have to be written.C、The leading zeroes in any 16 - bit segment do not have to be written.D、Any single, continuous string of one or more 16 - bit segments that consists of all zeroes can be represented with a double colon.E、The maximum number of times a double colon can replace a 16 - bit segment that consists of all zeroes is two.F、Two zeroes in the middle of any 16 -bit segment do not have to be written.
考题
Which two statements are true about using IPv4 and IPv6 simultaneously on a network segment? （）A、IPv6 allows a host to create its own IPv6 address that will allow it to communicate to other devices on a network configured via DHCP. IPv4 does not provide a similar capability for hosts.B、IPv6 provides for more host IP addresses but IPv4 provides for more network addresses.C、Hosts can be configured to receive both IPv4 and IPv6 addresses via DHCP.D、Host configuration options for IPv4 can be either statically assigned or assigned via DHCP.Host configuration options for IPv6 can be statically assigned only.E、IPv4 and IPv6 addresses c an be simultaneously assigned to a host but not to a router interface.
考题
Which two statements correctly describe the relation between a data file and the logical databasestructures（）A、An extent cannot spread across data files.B、A segment cannot spread across data files.C、A data file can belong to only one tablespace.D、A data file can have only one segment created in it.E、A data block can spread across multiple data files as it can consist of multiple operating system （OS） blocks.
考题
Which statement is correct regarding IPv6 addresses?（）A、An IPv6 address consists of 128 bits separated into eight 16-bit hexadecimal sections.B、An IPv6 address consists of 64 bits separated into four 16-bit hexadecimal sections.C、An IPv6 address consists of 128 bits separated into sixteen 8-bit hexadecimal sections.D、An IPv6 address consists of 64 bits separated into eight 8-bit hexadecimal sections.
考题
What is the maximum number of 220V power supplies that can be in a UCS chassis?（）A、twoB、fourC、twice the non-redundant configuration required to power the chassisD、three times the non-redundant configuration required to power the chassis
考题
When the system upon which a transport entity is running fails and subsequently restarts,the(21) information of all active connections is lost. The affected connections become half-open, as the side that did not fail does not yet realize the problem.The still active side of a half-open connections can close the connection using a(22)timer. This timer measures the time the transport machine will continue to await an (23) of a transmitted segment after the segment has been retransmitted the maximum number of times.When the timer (24),the transport entity assumes that either the other transport entity or the intervening network has failed. As a result, the timer closes the connection, and signals an abnormal close to the TS user. In the event that a transport entity fails and quickly restarts, half-open connections can be terminated more quickly by the use of the RST segment, the failed side returns an RST i to every segment i that it receives. When the RST i reaches the other side, it must be checked for validity based on the (25) number i, as the RST could be in response to an old segment. If the reset is valid, the transport entity performs an abnormal termination.
空白处（25）应选择（）A、sequenceB、acknowledgmentC、connectionD、message
考题
You specified segment space management as automatic for a tablespace. What effect would this have on space management？（）A、Extents would be managed by the freelists.B、The segment would be managed by bitmaps.C、The segment would be managed by the freelists.D、Free space would be managed by the data dictionary.
考题
Which two statements are true regarding transactions in an Oracle database（）A、Multiple transactions can use the same undo segment.B、A transaction is assigned an undo segment when it is started.C、More than one transaction cannot share the same extent in the undo tablespace.D、The transactions use system undo segment to store undo data if all the segments in the undo tablespaceare used.
考题
You have a long-running process you want to assign to a specific UNDO segment brought online for that express purpose. You are not using automatic UNDO management. What statement can be used for this task? （）A、ALTER DATABASE B、SET TRANSACTION C、ALTER ROLLBACK SEGMENT D、ALTER TABLE
考题
Your company is designing its public network. The network will use an IPv4 range of 131.107.40.0/22.The network must be configured as shown in the following exhibit.You need to configure subnets for each segment. Which network addresses should you assign？（）A、Segment A: 131.107.40.0/23 Segment B: 131.107.42.0/24 Segment C: 131.107.43.0/25 Segment D: 131.107.43.128/27B、Segment A: 131.107.40.0/25 Segment B: 131.107.40.128/26 Segment C: 131.107.43.192/27 Segment D: 131.107.43.224/30C、Segment A: 131.107.40.0/23 Segment B: 131.107.41.0/24Segment C: 131.107.41.128/25 Segment D: 131.107.43.0/27D、Segment A: 131.107.40.128/23 Segment B: 131.107.43.0/24Segment C: 131.107.44.0/25 Segment D: 131.107.44.128/27
考题
You are the administrator of a Windows XP Professional computer. You run five 16-bit applications on the computer. You want to monitor the performance of the computer when all five applications run at the same time. You use System Monitor to collect the performance data. The performance counters you want to include in your analysis are IO Read Bytes/sec, IO Write Bytes/sec, and Page Faults/sec. You want to ensure that you can collect these counters for each application. What should you do?（） A、Run the five 16-bit applications in one process. Monitor each thread of Ntvdm.exe. B、Run each of the five 16-bit applications in its own memory space. Monitor each instance of Ntvdm.exe. C、Run the five 16-bit applications in Windows 95 compatibility mode. Monitor each instance of the applications. D、Start the five 16-bit applications by using the Start /normal command. Monitor each instance of the applications.
考题
You have a single network segment. All servers run Windows Server 2003 Service Pack 2 (SP2). You have a DHCP server named Server1. Client computers receive IP addresses from Server1. You add a second network segment separated by a RFC 1542-compliant router. You need to ensure that computers in the new network segment can receive their IP configurations from Server1. You make the appropriate configuration changes on the router. What should you do on Server1?（）A、Create a new scope.B、Configure a DHCP Relay Agent.C、Add an Extensions Path scope option.D、Create a new exclusion range in the existing scope.
考题
单选题Your company is designing its public network. The network will use an IPv4 range of 131.107.40.0/22.The network must be configured as shown in the following exhibit.You need to configure subnets for each segment. Which network addresses should you assign？（）A
Segment A: 131.107.40.0/23 Segment B: 131.107.42.0/24 Segment C: 131.107.43.0/25 Segment D: 131.107.43.128/27B
Segment A: 131.107.40.0/25 Segment B: 131.107.40.128/26 Segment C: 131.107.43.192/27 Segment D: 131.107.43.224/30C
Segment A: 131.107.40.0/23 Segment B: 131.107.41.0/24Segment C: 131.107.41.128/25 Segment D: 131.107.43.0/27D
Segment A: 131.107.40.128/23 Segment B: 131.107.43.0/24Segment C: 131.107.44.0/25 Segment D: 131.107.44.128/27
考题
多选题Which two statements are true regarding transactions in an Oracle database（）AMultiple transactions can use the same undo segment.BA transaction is assigned an undo segment when it is started.CMore than one transaction cannot share the same extent in the undo tablespace.DThe transactions use system undo segment to store undo data if all the segments in the undo tablespaceare used.
考题
单选题You specified segment space management as automatic for a tablespace. What effect would this have on space management？（）A
Extents would be managed by the freelists.B
The segment would be managed by bitmaps.C
The segment would be managed by the freelists.D
Free space would be managed by the data dictionary.
考题
单选题Which statement is correct regarding IPv6 addresses?（）A
An IPv6 address consists of 128 bits separated into eight 16-bit hexadecimal sections.B
An IPv6 address consists of 64 bits separated into four 16-bit hexadecimal sections.C
An IPv6 address consists of 128 bits separated into sixteen 8-bit hexadecimal sections.D
An IPv6 address consists of 64 bits separated into eight 8-bit hexadecimal sections.
考题
单选题The Testking corporate LAN consists of one large flat network. You decide to segment this LAN into two separate networks with a router. What will be the affect of this change?（）A
The number of broadcast domains will be decreased.B
It will make the broadcasting of traffic between domains more efficient between segments.C
It will increase the number of collisions.D
It will prevent segment 1's broadcasts from getting to segment 2.E
It will connect segment 1's broadcasts to segment 2.
考题
多选题What are two rules for compacting IPv6 addresses？（）AThe maximum number of times a double colon can replace a 16-bit segment that consists of all zeroes is twoBThe leading zeroes in any 16-bit segment do not have to be written.CEvery 16-bit segment that consists of all zeroes can be represented with a single colonDThe trailing zeroes in any 16-bit segment do not have to be written.EAny single， continuous string of one or more 16-bit segments that consists of all zeroes can be represented with a double colonFTwo zeroes in the middle of any 16-bit segment do not have to be written
考题
多选题What are two rules for compacting IPv6 addresses?（）AEvery 16 - bit segment segment that consists of all zeroes can be represented with a single colon.BThe trailing zeroes in any 16 - bit segment do not have to be written.CThe leading zeroes in any 16 - bit segment do not have to be written.DAny single, continuous string of one or more 16 - bit segments that consists of all zeroes can be represented with a double colon.EThe maximum number of times a double colon can replace a 16 - bit segment that consists of all zeroes is two.FTwo zeroes in the middle of any 16 -bit segment do not have to be written.
考题
多选题Which two statements correctly describe the relation between a data file and the logical database structures（）AAn extent cannot spread across data files.BA segment cannot spread across data files.CA data file can belong to only one tablespace.DA data file can have only one segment created in it.EA data block can spread across multiple data files as it can consist of multiple operating system （OS）blocks
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