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单选题
有如下程序:#includeusing namespace std;class Apublic:static int a;void init()a=1;A(int a=2) init(); a++;;int A::a=0;A obj;int main()cout<
A

0

B

1

C

2

D

3


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参考解析
解析:
在C++中,当标识符的作用域发生重叠时,在一个函数中声明的标识符可以屏蔽函数外声明的标识符或全局标识符。声明类A的全局对象时,构造函数首先调用init函数,a=1,但由于静态成员变量a被构造函数内部的形参a所屏蔽,所以a++改变的是形参a的值,对静态成员变量a没有影响。
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