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在在SQL Server 2000中,设有课程表(课程号,课程名,学分,开课学期),现要在此关系表上建立一个查询指定学期开设的课程总门数和总学分数的内嵌表值函数,函数名为f _FindTotal。实现这个函数的正确代码是
A.CREATE FUNCTION f_FindTotal(@semester int) RETURNS table AS RETURN( SELECT COUNT(课程号)as课程门数, SUM(学分)as总学分FROM课程表 WHERE开课学期 = @ semester)
B.CREATE FUNCTION f_FindTotal(@semester int) RETURNS table AS RETURN( SELECT COUNT(课程号)as课程门数, COUNT(学分)as总学分FROM课程表 WHERE开课学期 = @semester)
C.CREATE FUNCTION f_FindTotal(@semester int) RETURNS table AS RETURN( SELECT SUM(课程号)as课程门数, SUM(学分)as总学分FROM课程表 WHERE开课学期= @semester)
D.CREATE FUNCTION f_FindTotal(@semester int) RETURNS table AS RETURN( SELECT SUM(课程号)as课程门数, COUNT(学分)as 总学分FROM课程表 WHERE开课学期 = @semester)
A、培训改卷教师
B、制作答题卡
C、扫描答题卡
D、网上阅卷病控制评分误差
请将每一个空的正确答案写在答题卡【1】~【20】序号的横线上,答在试卷上不得分。
1.计算并填写下表
(1)
【1】B类【解析】题目中给定的lP地址191.23.181.13的第一字节范围属于128~191之间,可以判断该IP地址属于B类地址;或者将IP 地址写成二进制形式为:10111111.0 0010111.10110101.00001101,第一字节以“10”开头,也可以判断出该lP地址属于B类地址。
【2】191.23.128.0 【解析】由题目知,该lP地址的子网掩码为255.255.192.0,写成二进制表示法为11111111.11111111.11000000.00 00000,子网掩码的前18位为“1”,说明前18位为网络号,后14位为主机号。用子网掩码与lP地址做“与”运算,得到网络地址为 10111111.00010111.10000000.00000000,写成十进制即191.23.128.0 或191.23.128.0/18。
【3】191.23.191.255 【解析】把lP地址的主机号全部置“1”即可得到直接广播地址,即10111111.00 010111.10111111.11111111,写成十进制,即 191.23.191.255。
【4】 0.0.53.13 【解析】将网络号地址全部置“0”,便可得到该lP的主机号,即00000000.00000000.00110101.00001101,写成十进制即0.0.53.13。
【5】191.23.191.254 【解析】由于主机号全置“1”时为广播地址,是不可用的IP 地址。所以最后一个lP地址为主机号的广播地址减去l,即 191.23.191.254.
英语四级考试答题卡1到底分不分AB卷的??
第一卷(作文那张)不分AB,第二卷才分.
下列哪些考试行为属于考生违纪:()
- A、考生未经监考员同意,在考试过程中擅自离开考场。
- B、考生将试卷、答题卡、草稿纸等考试用纸带出考场。
- C、考生用规定以外的笔或者纸答题,或者在答题卡规定以外的地方书写姓名、准考证号。
- D、考生在答题卡上填写与本人身份不符的姓名和准考证号等信息。
正确答案:A,B,C
B卷第二学期程序设计语言(C)参照答案和评分原则 专业班级 姓 名 学 号 开课系室 软件工程系 考试日期 7月3日 题 号一二三总分得 分阅卷人程序设计语言(C)试卷(B卷)答题卡阐明:1选择题和判断题必须填在答题卡上才有效,综述题写在指定位置。得分 2本试卷共13页,不得拆开。单选题(对旳旳答案涂黑或画圈,20分)1ABD11ABD2ACD12BCD3BCD13ACD4ACD14ABC5BCD15BCD6ACD16ACD7ABC17ABC8ABD18ACD9ABD19ACD10ACD20ABC得分读程序填空题(在空格处填写对旳答案,20分)12a10或a&aia i-1i%4=0a10-1-i *q+ = *p+或*(q+i)=*(p+i)或bi=ai0q=bi得分三、编程题(60分,在下面旳空白处编写程序)1、编程计算下面函数旳值,其中x由键盘输入。(12分) -1 x-1 y= -1x1(x+1)2 x1参照答案:#include main() int x; float y; printf(input x n); scanf(%d,&x); if(x-1 & x1) y=exp(x); else y=(x+1)*(x+1); printf(%f,y);评分原则:头文献、程序框架占2分;读入x值占1分;每个分支语句各占3分,共9分。2. 一球从200米高度自由落下,每次落地后反跳回原高度旳一半再落下,求它在第15次落地时,共通过多少米?第15次反弹多高?(6分)参照答案:#include main( ) float sn=200.0,hn=sn/2; int n; for(n=2;n=15;n+) sn=sn+2*hn; hn=hn/2; printf(“第15次落地共通过%f米n”,sn); printf(“第15次反弹%f米n”,hn); 评分原则:头文献、程序框架占2分;变量初始化占1分;for循环占3分。3.编写一函数sum,求二维数组(M*M)上三角(含对角线)之和。(12分)参照答案:int sum(int aMM) int s=0,k,n; /*变量
监考员处理缺考考生试卷、答题卡及空白试卷、答题卡操作为()。
- A、将缺考考生的条形码粘贴在《考场情况记录表》上规定区域内
- B、用0.7黑色墨水的签字笔在答题卡袋封面上填缺考准考证号及相关内容
- C、用0.7黑色墨水的签字笔在缺考答题卡上填写缺考考生姓名和准考证号
- D、用0.7黑色墨水的签字笔在《考场情况记录表》上规定区域填写缺考考生姓名和准考证号
- E、用0.7黑色墨水的签字笔分别在缺考考生试卷、答题卡和尾考场的空白试卷、空白答题卡左上角空白处注明“缺考”或“空白”字样
- F、用2B铅笔填涂缺考考生答题卡的缺考标记
正确答案:A,B,C,E
监考员对缺考考生的答题卡处理是()
- A、在答题卡右上角注明“缺考”字样
- B、在答题卡上填涂缺考标记
- C、在答题卡指定位置填写姓名、准考证号
- D、在答题卡指定位置粘贴准考证条形码
- E、在答题卡左上角注明“缺考”字样
正确答案:C,E
考生领到答题卡、试卷后,监考员应指导考生在在规定时间内和指定位置准确填写()等。
- A、姓名
- B、座位号
- C、准考证号
- D、考籍号
- E、考生号
正确答案:A,C
规范用语提示语内容:“考试结束信号发出,大家必须立即停止答题,将试卷、答题卡按页码顺序清点放好,上下顺序是:答题卡在上,下边依次为试卷、草稿纸。整理好答题卡、试卷、草稿纸,待监考员收齐、核对无误后,大家方可依次退场”的时间为()
- A、考前15分钟
- B、考前5分钟
- C、考试结束前15分钟
- D、考试结束
正确答案:A
考试结束信号发出,监考员回收试卷、答题卡操作程序()
- A、按规定将答题卡清点、整理、排序、装袋;按规定将试卷进行清点、整理。
- B、要求考生立即停止答卷
- C、监考员乙逐一检查、核对考生所填写的准考证号是否准确,试卷页码是否完整,同时收取答题卡、试卷、草稿纸
- D、整理好草稿纸并注明考场号、考试时间、监考员姓名,与试卷清点、整理后一同装入试卷袋
- E、再次核对答题卡袋封面要求填写的内容、《考场情况记录表》的内容
- F、清理考场,检查课桌抽屉,关好门窗,封闭考场
正确答案:A,B,C,D,E,F
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